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ipn [44]
3 years ago
10

Which percentage is the best estimate for the shaded area under this normal curve?

Mathematics
1 answer:
borishaifa [10]3 years ago
7 0
<h3>Answer: B)  77.5%</h3>

=========================================================

Explanation:

It appears that -20 is the mean. It's not entirely clear however. If that assumption is correct, then the distance from -30 to -20 is 10 units. So the left endpoint is 1 standard deviation below the mean (because the standard deviation is 10 units).

Recall that through the empirical rule, roughly 68% of the distribution is within 1 standard deviation of the mean. This cuts in half to 34%. So the area from x = -30 to x = -20 is roughly 0.34

We'll use this value later so let A = 0.34

-------------------

The area under the curve from x = -20 to x = -10 is also 0.34

The area under the curve from x = -20 to x = 0 is 0.95/2 = 0.475

For the second part there, I'm using the idea that 95% of the normal distribution (roughly) is within 2 standard deviations of the mean.

So the area from x = -20 to x = -5 is somewhere between 0.34 and 0.475

Let B = 0.34 and C = 0.475

-------------------

The full shaded blue area is somewhere between A+B = 0.34+0.34 = 0.68 and A+C = 0.34+0.475 = 0.815

Based on that alone, the answer is between B and C.

-------------------

Unfortunately, we can't nail down an actual value unless we use a Z table or a calculator.

When I use a calculator, I'm getting 0.7745 (approximate) which rounds to 0.775 and converts to 77.5%

As for how to get this without a table or calculator, I'm not entirely sure what your teacher wanted you to do.

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Suppose it is known from large amounts of historical data that X, the number of cars that arrive at a specific intersection duri
Andrew [12]

Answer:

a) P(x>8) = 0.3937

b)  P(x = 2) =0.04661

Step-by-step explanation:

a) From to find the probabilty that in this specific time period, more than 8 cars arrive at the intesection, we use the probability function thus

P(x>8) = 1 - P(x≤8),  Cause you can use the complement for calculate this probability , then:

P(x≤8) = \frac{e^{-6}*6^{0} }{0!}+\frac{e^{-6}*6^{1} }{1!}+\frac{e^{-6}*6^{2} }{2!}+... , until x= 8, then you obtain:

P(x≤8)=0.6063 and

P(x>8) = 1 - P(x≤8)= 1-0.6063 = 0.3937

b) P(x=2)= \frac{e^{-6}*6^{2}  }{2!}

 P(x = 2) =0.04661

3 0
3 years ago
A ball Is dropped from a height of 100'. The height of the ball can be determined using the equation h = -16t^2+ 100, Where H is
katen-ka-za [31]

Answer:

<h3>2.5secs</h3>

Step-by-step explanation:

Given the height of the ball modeled by the equation  h = -16t^2+ 100, where

h is the height

t is in seconds

We can find the time taken by the ball to reach the ground.

The ball reaches the ground when the height h = 0

Substitute h = 0 into the equation and find t;

0 = -16t^2+ 100

16t^2 = 100

t^2 = 100/16

t = √100/16

t = 10/4

t = 2.5secs

Hence the ball reaches the ground after 2.5secs

6 0
3 years ago
How do I show my work for 52 divided by 8
Elis [28]
<span>8/52

8x4=32

52-32= 20

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20-16= 4

8 x 0.5= 4

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Add up all the numbers in bold.

The answer should be 6.5</span>
5 0
4 years ago
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dlinn [17]

Answer:

c = -4    d = 6

Step-by-step explanation:

8 - 2d = c     4c + 3d = 2

                    4(8 - 2d) + 3d = 2

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8 - 2(6) = c

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3 0
3 years ago
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