Answer:
P=0.147
Step-by-step explanation:
As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2
We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.
We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) . To find the required probability 3 mentioned probabilitie have to be summarized.
So P(9/16 )= C16 9 * P(good brakes)^9*Q(bad brakes)^7
P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02
P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007
P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12
P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147
Answer:
D
Step-by-step explanation:
Let the number of geese be x.
Then number of goats is 22-x.
A goose has 2 legs, and a goat has 4.
There are a total of 82 legs.
So,
2x + 4(22-x) = 82
2x + 88 - 4x = 82
-2x = -6
x = 3
There are 3 geese and (22-3=) 19 goats.
Please mark Brainliest if this helps and feel free to ask doubts!
You could rewrite
as
and be tempted to cancel out the factors of
. But this cancellation is only valid when
.
When
, you end up with the indeterminate form
, which is why
is not a zero.
Answer:
If you cube the numbers in the left column, you get the numbers in the right column! We can figure this out by understanding that 1^3 = 1, 3^3 = 27, and 6^3 = 216. Then it all falls into place!
1 -> 1
2 -> 8
3 -> 27
5 -> 125
6 -> 216
11 -> 1331
8 -> 512
10 -> 1000
7 -> 343
14 -> 2744
p -> 
-> q
