I need the answer to the Problem RIGHT NOW

Tcecarenko [31]

Since CB || ED and CB = ED,

by the alternate interior angles theorem,
mE = mC, and mD = mB.

with CB = ED, we can conclude that CBF = EDF, by SAS congruent theorem.

7 0

3 years ago

What is the standard form of the quadratic equation y=−1/2(x+5)^2−10?

mr Goodwill [35]

Answer:

y = -1/2x^2 -5x -45/2

Step-by-step explanation:

Multiply it out and collect terms.

y = -1/2(x^2 +10x +25) -10 . . . . . expand the square

y = -1/2x^2 -5x -25/2 -20/2 . . . eliminate parentheses

y = -1/2x^2 -5x -45/2 . . . . . . . . collect terms

3 0

4 years ago

If an element has 7 valence electrons, how many dots will be in the elements dot diagram?

shepuryov [24]

If I understand the question correctly, dots are written around the symbol to represent valence electrons, so 7 dots would be in the elements dot diagram. The element is in Group 17 with 4 other elements.

4 0

3 years ago

Allison bought 12 books. One sixth of the books she bought were on sale. How many of the books were on sale

Jlenok [28]

2
Because 12 divided by 6 equals 2 because you were trying to find one sixth

8 0

3 years ago

Because of the relatively high interest rates, most consumers attempt to pay off their credit card bills promptly. However, this

BigorU [14]

Answer:

a. 0.4129 = 41.29% of the bank's Visa cardholders pay more than 29 dollars in interest.

b. 0.1867 = 18.67% of the bank's Visa cardholders pay more than 35 dollars in interest.

c. 0.0742 = 7.42% of the bank's Visa cardholders pay less than 14 dollars in interest.

d. An interest payment of $35.2 is exceeded by only 18% of the bank's Visa cardholders.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 27 dollars and a standard deviation of 9 dollars.

This means that $\mu = 27, \sigma = 9$

A. What proportion of the bank's Visa cardholders pay more than 29 dollars in interest?

This is 1 subtracted by the p-value of Z when X = 29, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{29 - 27}{9}$

$Z = 0.22$

$Z = 0.22$ has a p-value of 0.5871.

1 - 0.5871 = 0.4129

0.4129 = 41.29% of the bank's Visa cardholders pay more than 29 dollars in interest.

B. What proportion of the bank's Visa cardholders pay more than 35 dollars in interest?

This is 1 subtracted by the p-value of Z when X = 35, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{35 - 27}{9}$

$Z = 0.89$

$Z = 0.89$ has a p-value of 0.8133.

1 - 0.8133 = 0.1867

0.1867 = 18.67% of the bank's Visa cardholders pay more than 35 dollars in interest.

C. What proportion of the bank's Visa cardholders pay less than 14 dollars in interest?

This is the p-value of Z when X = 14. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{14 - 27}{9}$

$Z = -1.445$

$Z = -1.445$ has a p-value of 0.0742.

0.0742 = 7.42% of the bank's Visa cardholders pay less than 14 dollars in interest.

D. What interest payment is exceeded by only 18% of the bank's Visa cardholders?

This is the 100 - 18 = 82nd percentile, which is X when Z has a p-value of 0.82, so X when Z = 0.915.

$Z = \frac{X - \mu}{\sigma}$

$0.915 = \frac{X - 27}{9}$

$X - 27 = 0.915*9$

$X = 35.2$

An interest payment of $35.2 is exceeded by only 18% of the bank's Visa cardholders.

7 0

3 years ago