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Anarel [89]
4 years ago
5

What is the standard form of the quadratic equation y=−1/2(x+5)^2−10?

Mathematics
1 answer:
mr Goodwill [35]4 years ago
3 0

Answer:

  y = -1/2x^2 -5x -45/2

Step-by-step explanation:

Multiply it out and collect terms.

  y = -1/2(x^2 +10x +25) -10 . . . . . expand the square

  y = -1/2x^2 -5x -25/2 -20/2 . . . eliminate parentheses

  y = -1/2x^2 -5x -45/2 . . . . . . . . collect terms

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Solve for a.<br><br> ​ 1/3(21−3a)=6−a​
Tems11 [23]
<span>1/3(21-3a)=6-a
I simplified the equation to the form, which is simple to understand
<span>1/3(21-3a)=6-a
Simplifying:
<span> + 0.333333333333*(21-3a)=6-a
Reorder the terms in parentheses
<span>+(+7-1a)=6-a
Remove unnecessary parentheses
<span>+7-1a=+6-a
We move all terms containing a to the left and all other terms to the right.
<span>-1a+1a=+6-7
We simplify left and right side of the equation.
<span>a=-1
<span>0=-1
The left and right sides are not equal, therefore there is no solution. This equation is invalid
Hope this helped

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3 0
3 years ago
Read 2 more answers
How to write a real-world situation that could be modeled by the equation 3 2/3x=5/6x-7/8?
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I hope this helps you

8 0
4 years ago
Suppose that MNO is isosceles with base NM. Suppose also that =m∠N+4x7° and =m∠M+2x29°. Find the degree measure of each angle in
chubhunter [2.5K]

Answer:

m∠N = 51°

m∠M = 31°

m∠O = 98°

Step-by-step explanation:

It is given that ΔMNO is an isosceles triangle with base NM.

m∠N = (4x + 7)° and m∠M = (2x + 29)°

By the property of an isosceles triangle,

Two legs of an isosceles triangle are equal in measure.

ON ≅ OM

And angles opposite to these equal sides measure the same.

m∠N = m∠M

(4x + 7) = (2x + 29)

4x - 2x = 29 - 7

2x = 22

x = 11

m∠N = (4x + 7)° = 51°

m∠M = (2x + 9)° = 31°

m∠O = 180° - (m∠N + m∠M)

         = 180° - (51° + 31°)

         = 180° - 82°

         = 98°

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3 years ago
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I ran 10 miles in 2 hours. What was my average speed?
gogolik [260]

Answer:

5mph

Step-by-step explanation:

10/2 = 5

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