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mina [271]
3 years ago
6

If you randomly choose two letters from the word "JANUARY ", find the probability that you choose letter J first and then A afte

r replacing the first. Round answer to nearest tenth and include percent sign. Also, does this represent an independent or dependent scenario?
Mathematics
1 answer:
miss Akunina [59]3 years ago
3 0

Answer:

2.0%

Step-by-step explanation:

The probability of two events happening in the sequence is calculated by multiplying the probability of each event happening separately by one another. Since there are a total of 7 letters in this word then the probability of choosing one letter correctly is \frac{1}{7} . Since the first letter is replaced before choosing the second letter the probability remains the same. Therefore, the sequence would be the following...

\frac{1}{7} * \frac{1}{7} = 0.020164 or 2.0%

This is an independent scenario because it does not depend on any external factors and under these circumstances the percentage will remain the same.

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Write an equation in point slope form that represents the line that passes through the point (-2,-1) and has a slope of 5. Then,
jeka57 [31]
Point-slope equation=y+1=5(x+2)
slope intercept form=5x+9
8 0
2 years ago
The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?
Anit [1.1K]

Answer: The correct option is A.

Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.

We are given the resultant polynomial which is : 8d^5-3c^3d^2+5c^2d^3-4cd^4+9

One of the polynomial which are added up is : 2d^5-c^3d^2+8cd^4+1

Let the other polynomial be 'x'

According to the question:

8d^5-3c^3d^2+5c^2d^3-4cd^4+9=x+(2d^5-c^3d^2+8cd^4+1)

x=8d^5-3c^3d^2+5c^2d^3-4cd^4+9-(2d^5-c^3d^2+8cd^4+1)

Solving the like terms in above equation we get:

x=(8d^5-2d^5)+(-3c^3d^2+c^3d^2)+(5c^2d^3)+(-4cd^4-8cd^4)+(9-1)

x=6d^5-2c^3d^2+5c^2d^3-12cd^4+8

Hence, the correct option is A.

5 0
2 years ago
Read 2 more answers
The figure here shows triangle AOC inscribed in the region cut from the parabola y=x^2 by the line y=a^2. Find the limit of the
aleksandrvk [35]
Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =

(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =

= 2a^3 - 2(a^3)/3 = [4/3](a^3)

Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3

ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =

Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
 



3 0
2 years ago
Find the greatest common factor of 210, 84, and 56
mr Goodwill [35]
To get the Greates Common Factor (GCF) of 84 and 210 we need to factor each value first and then we choose all the copies of factors and multiply them: 

<span><span>84:   223 7</span><span>210:   2 357</span><span>GCF:   2 3 7</span></span>

<span>The Greates Common Factor (GCF) is:   2 x 3 x 7 = 42</span>

3 0
2 years ago
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Find the percent of increase to the nearest whole from 12 to 20
ankoles [38]

Answer:

The answer is

<h2>67\%</h2>

Step-by-step explanation:

To find the percentage increase we use the formula

<h3>Percentage \:   change =  \frac{change}{original \:  \: quantity}  \times 100\%</h3>

From the question

The original value = 12

To find the change we subtract the smaller value from the larger one

That's

Change = 20 - 12 = 8

So the percentage increase is

<h3>\frac{8}{12}  \times 100 \%\\  =  \frac{2}{3}  \times 100\% \\  = 66.67\%</h3>

We have the final answer as

67\% to the nearest whole number

Hope this helps you

3 0
3 years ago
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