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3 years ago

14

Guidelines for a wheelchair ramp suggest that the ratio of the rise to the run be no greater than 1:12.design a wheelchair ramp

that provides access to a building with a front door 2.5 feet above the sidewalk

1 answer:

OLEGan [10]3 years ago

4 0

I have no idea tbh. I will try to find how to do it and help you!

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Please report my account

Fiesta28 [93]

it's good to get a new rank

like you seems to be genius in another id be genius In this id too

its not a misfortune to be sad<em />

6 0

3 years ago

Read 2 more answers

Find the perimeter of WXYZ. Round to the nearest tenth if necessary.

yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

$W(-1, 1) = (x_1, y_1)$

$X(1, 2) = (x_2, y_2)$

Plug in the values

$WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}$

$WX = \sqrt{(2)^2 + (1)^2}$

$WX = \sqrt{4 + 1}$

$WX = \sqrt{5}$

$WX = 2.24$

✔️Distance between X(1, 2) and Y(2, -4)

Let,

$X(1, 2) = (x_1, y_1)$

$Y(2, -4) = (x_2, y_2)$

Plug in the values

$XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}$

$XY = \sqrt{(1)^2 + (-6)^2}$

$XY = \sqrt{1 + 36}$

$XY = \sqrt{37}$

$XY = 6.08$

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

$Y(2, -4) = (x_1, y_1)$

$Z(-2, -1) = (x_2, y_2)$

Plug in the values

$YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}$

$YZ = \sqrt{(-4)^2 + (3)^2}$

$YZ = \sqrt{16 + 9}$

$YZ = \sqrt{25}$

$YZ = 5$

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

$Z(-2, -1) = (x_1, y_1)$

$W(-1, 1) = (x_2, y_2)$

Plug in the values

$ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}$

$ZW = \sqrt{(1)^2 + (2)^2}$

$ZW = \sqrt{1 + 4}$

$ZW = \sqrt{5}$

$ZW = 2.24$

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0

3 years ago

Calculate the frequency of a wave with a speed of 250m/s and a wavelength of 50m.

WARRIOR [948]

Answer:

<h3>formulas</h3>

<em><u>frequency</u></em><em><u>=</u></em><em><u>spee</u></em><em><u>d</u></em><em><u>/</u></em><em><u>wavele</u></em><em><u>ngth</u></em>

<em><u>f</u></em><em><u>=</u></em><em><u>2</u></em><em><u>5</u></em><em><u>0</u></em><em><u>/</u></em><em><u>5</u></em><em><u>0</u></em>

<em><u>f</u></em><em><u>=</u></em><em><u>5</u></em><em><u>0</u></em><em><u>h</u></em><em><u>z</u></em>

7 0

2 years ago

What is the parallel slope intercept form pls answerr

lys-0071 [83]

Answer:

the paralell slope is -4. The slope intercept equation is -4x-4

Step-by-step explanation:

hope this helps!

7 0

2 years ago

I don't know how to do this please help explain how to do it aswell as give the answer so i understand

Zinaida [17]

<u>We are given:</u>

The function: y = -16t² + 64

where y is the height from ground, t seconds after falling

<u>Part A:</u>

when the droplet would hit the ground, it's height from the ground will be 0

replacing that in the given function:

0 = -16t² + 64

16t² = 64 [adding 16t² on both sides]

t² = 4 [dividing both sides by 16]

t = 2 seconds [taking square root of both sides]

<u>Part B:</u>

for second droplet,

height from ground = 16 feet

time taken = t seconds

acceleration due to gravity = 10 m/s²

initial velocity = 0 m/s

h = ut + (1/2)at² [second equation of motion]

16 = (0)(t) + (1/2)(10)(t²)

16 = 5t²

t² = 16/5

t = 1.8 seconds (approx)

Therefore, the second droplet takes the least amount time to hit the ground

4 0

3 years ago