A particular electric utility charges customers different rates depending on their daily rate of energy consumption: $0.05/kWh u
1 answer:
Answer:
(a) the number of 100W light bulbs is 11
(b) the daily cost of 2000 kW is $4,800
Step-by-step explanation:
charge of energy consumption up to 20 kWh = $0.05/kWh
charge of energy consumption above 20 kWh = $0.10/kWh
(a) number of 100 W light bulbs that can be run continuously for less than $10 per week
Total energy consumed by 100 W in 1 week = (0.1 kW) x (7 x 24 h)
= 16.8 kWh
Charge associated with this consumption = $0.05/kWh
let the number of 100 W light bulbs = n
Since 0.9 is not a whole number, the number of 100 W light bulbs is 11.
(b) if 2000 kW is used continuously
total energy consumption = 2000 kW x 24 h = 48,000 kWh
The daily cost is calculated as;
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Based on the weight and the model that is given, it should be noted that W(t) in radians will be W(t) = 0.9cos(2πt/366) + 8.2.
<h3>How to calculate the radian.</h3>
From the information, W(t) = a cos(bt) + d. Firstly, calculate the phase shift, b. At t= 0, the dog is at maximum weight, so the cosine function is also at a maximum. The cosine function is not shifted, so b = 1.
Then calculate d. The dog's average weight is 8.2 kg, so the mid-line d = 8.2. W(t) = a cos t + 8.2. Then calculate a, the dog's maximum weight is 9.1 kg. The deviation from the average is 9.1 kg - 8.2 kg = 0.9 kg. W(t) = 0.9cost + 8.2
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Answer:
- g(2.95) ≈ -1.8; g(3.05) ≈ -0.2
- A) tangents are increasing in slope, so the tangent is below the curve, and estimates are too small.
Step-by-step explanation:
(a) The linear approximation of g(x) at x=b will be ...
g(x) ≈ g'(b)(x -b) +g(b)
Using the given relations, this is ...
g'(3) = 3² +7 = 16
g(x) ≈ 16(x -3) -1
Then the points of interest are ...
g(2.95) ≈ 16(2.95 -3) -1 = -1.8
g(3.05) ≈ 16(3.05 -3) -1 = -0.2
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(b) At x=3, the slope of the curve is increasing, so the tangent lies below the curve. The estimates are too small. (Matches description A.)
