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Sloan [31]
2 years ago
8

A particular electric utility charges customers different rates depending on their daily rate of energy consumption: $0.05/kWh u

p to 20 kWh, and $0.10/kWh for all energy usage above 20 kWh in any 24-hour period. (a) Calculate how many 100 W light bulbs can be run continuously for less than $10 per week. (b) Calculate the daily energy cost if 2000 kW of power is used continuously.
Mathematics
1 answer:
Yanka [14]2 years ago
4 0

Answer:

(a) the number of 100W light bulbs is 11

(b) the daily cost of 2000 kW is $4,800

Step-by-step explanation:

charge of energy consumption up to 20 kWh = $0.05/kWh

charge of energy consumption above 20 kWh = $0.10/kWh

(a) number of 100 W light bulbs that can be run continuously for less than $10 per week

Total energy consumed by 100 W in 1 week = (0.1 kW) x (7 x 24 h)

                                                                          = 16.8 kWh

Charge associated with this consumption = $0.05/kWh

let the number of 100 W light bulbs = n

n(\frac{\$ 0.05}{kWh} \times 16.8 kWh) = \$10\\\\n(0.84) = 10\\\\n = \frac{10}{0.84} \\\\n = 11.9

Since 0.9 is not a whole number, the number of 100 W light bulbs is 11.

(b) if 2000 kW is used continuously

total energy consumption = 2000 kW x 24 h = 48,000 kWh

The daily cost is calculated as;

= \frac{\$0.10 }{kWh}  \ \times \ 48,000 kWh\\\\= \$ 4,800

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Answer:

D

Step-by-step explanation:

This questions asks use to find what f(x) or y is, when x is equal to -2.

So, substitute -2 in for x in the equation.

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f(-2)=2(4)^-2

Evaluate the exponent. Negative exponents follow this rule:

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We have 4^-2. This will become 1/4^2 or 1/16

f(-2)=2(1/16)

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This fraction can be simplified. Both the numerator (top number) and denominator (bottom number) can be divided by 2.

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What set of reflections and rotations would carry rectangle ABCD onto itself? Parallelogram formed by ordered pairs A at negativ
Hoochie [10]

Answer:

Option (4).

Step-by-step explanation:

Let's take the coordinates of point A for the set of reflections and rotations given in the options.

Option (1). Rotate 180° → A(-4, 1) becomes (4, -1)

                Reflect over x-axis → (4, -1) becomes (4, 1)

                Reflect over the line y = x → (4, 1) becomes A'(1, 4)

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Option (2). Reflect across x-axis → A(-4, 1) will become (-4, -1)

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                  Reflect over the x-axis → (4, 1) becomes A'(4, -1)

Therefore, point A(-4, 1) doesn't overlap A'(4, -1).

Option (3). Rotate 180° → A(4, 1) becomes (-4, -1)

                  Reflect over the y-axis → (-4, -1) becomes (4, -1)

                  Reflected over y = x → (4, -1) becomes (-1, 4)

So the point A(4, 1) becomes A'(-1, 4) after the set of reflections,

Option (4). Reflect over the y axis → A(-4, 1) becomes (4, 1)

                 Reflect over the x-axis → (4, 1) becomes (4, -1)

                 Rotate 180° → (4, -1) becomes A'(-4, 1)

Therefore, point A will overlap itself following the set of transformations.

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