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GarryVolchara [31]
3 years ago
13

True of false A triangle cannot have more than one right angel

Mathematics
2 answers:
Stells [14]3 years ago
8 0

Answer:

False

Step-by-step explanation:

Ganezh [65]3 years ago
6 0

Answer:

false

Step-by-step explanation:

because if it did have more than one right angle, then it couldnt really be a triangle, it would just be looking like a square with one side gone.

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Simplify this algebraic expression completely. <br> 6x – 4(x + 3)
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6x - 4(x + 3)
6x -4x -12. Distribute
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5 0
3 years ago
Read 2 more answers
A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi
34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{X}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

\sigma_{X}=\sqrt{n}\sigma

It is provided that:

\mu=\$27\\\sigma=\$18\\n=310

As the sample size is quite large, i.e. <em>n</em> = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z

Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.

(b)

Let <em>s</em> denote the revenue of the store on the worst 1% of such days.

Then, P (S < s) = 0.01.

The corresponding <em>z-</em>value is, -2.33.

Compute the value of <em>s</em> as follows:

z=\frac{s-\mu_{X}}{\sigma_{X}}\\\\-2.33=\frac{s-8370}{316.923}\\\\s=8370-(2.33\times 316.923)\\\\s=7631.56941\\\\s\approx \$7,631.57

Thus, the revenue of the store on the worst 1% of such days is $7,631.57.

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2 years ago
Write the slope-intercept form of the equation of each line​
Vera_Pavlovna [14]

First let's talk about the blue line.

You can see its rising so its slope is certainly positive. But by how much is it rising? You can observe that each unit it rises it goes 1 forward and 1 up so its slope is the ratio of 1 up and 1 forward which is just 1.

We have thusly,

y=x+n

Now look at where blue line intercepts y-axis, -1. That is our n.

So the blue line has the equation of,

y=x-1

Next the black lines. The black lines are axes so their equations are a bit different.

First let's deal with x-axis, does it have slope? Yes but it is 0. The x-axis is still, not rising nor falling. Where does x-axis intercept y-axis? At 0. So the equation would be,

y=0x+0=0

Now we have y-axis. Does y axis have a slope? Yes but it is \infty. The y-axis rises infinitely in no run. Where does it intercept y-axis? Everywhere! So what should the equation be? What if we ask where does y-axis intercept x-axis and write its equation in terms of x. Y-axis intercepts x-axis at 0 which means its equation is,

x=0

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Hope this helps :)

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3 years ago
Name the ray in TWO different ways.<br> M N P
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MP
PM
Assuming your n is on a side
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2 years ago
CONSTRUCTION You are asked to copy a segment CD, construct a segment bisector by paper folding, and label the
lilavasa [31]

The steps on the construction of a segment bisector by paper folding, and label the midpoint M is given below.

<h3>What are the steps of this construction?</h3>

1. First, one need to open a Compass so that it is said to be more than half the length of the said segment.

2. Without altering it, with the aid of the compass, do  draw an art above and also below the said line segment from one of the segment endpoints.

3. Also without altering it and with use the compass, do draw another pair of arts from the other and points. One arc will be seen above the segment and the other or the second arc will be seen below.

4. Then do draw the point of intersection that is said to exist between the pair of arts below the line segment and also in-between the pair of arts as seen  below the line segment

5. Lastly, do make use of a straight edge to link the intersection points between the both pair of arts.

Learn more about segment bisector from

brainly.com/question/24736149

#SPJ1

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2 years ago
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