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Vilka [71]
3 years ago
15

Is landing on a number less than 5 on a 6 sided dice impossible,unlikely?equally likely,likely,certain

Mathematics
1 answer:
bulgar [2K]3 years ago
7 0
I would say Likely. Hope this helped!
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What set of values is apart of the solution set to the inequality 3.5p+14>7p
aalyn [17]

Answer:

q

Step-by-step explanation:

5 0
3 years ago
Can someone tell me the area of this please
Andru [333]

Answer: just multiply all sides with a calculator, that easy

Step-by-step explanation: or do you need help with solving it?

5 0
3 years ago
Read 2 more answers
Sabiendo que lo ancho de un terreno rectangular mide 24.7 m y que su perímetro es de 131.8 m. ¿Cuánto mide cada uno de sus lados
nadya68 [22]

Answer:

El perímetro de un terreno rectangular mide 48 m . Calcula sus dimensiones si el largo es el doble que el ancho.

Respuesta:

De largo mide 16m

De ancho mide 8m

Explicación paso a paso:

Perímetro = número de lados multiplicado por longitud del lado.

Formula: P = 2(a + b)  o    P = 2b + 2h

Donde: P = Rectángulo del perímetro

           a y b = Longitudes de lados

Asignamos las variables:

Largo = 2x

Ancho = x

Utilizamos la formula:

2(x) + 2(2x) = 48

2x + 4x = 48

6x = 48

x = 48/6

x = 8m  (ancho)

2x

2(8)

16m (largo)

Step-by-step explanation:

4 0
3 years ago
In a population of similar households, suppose the weekly supermarket expense for a typical household is normally distributed wi
Rina8888 [55]

Answer:

P(Y ≥ 15) = 0.763

Step-by-step explanation:

Given that:

Mean =135

standard deviation = 12

sample size n  = 50

sample mean \overline x = 140

Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses

Then,

X \sim N ( \mu \sigma)

The probability that X is greater than 140 is :

P(X>140) = 1 - P(X ≤ 140)

P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{140-135}{12})

P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{5}{12})

P(X>140) = 1 - P( Z\leq0.42)

From z tables,

P(X>140) = 1 - 0.6628

P(X>140) = 0.3372

Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140

Then;

Y \sim Binomial (np)

Y \sim Binomial (50,0.3372)

∴

P(Y ≥ 15) = 1- P(Y< 15)

P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )

P(Y \geq 15) = 1 - \begin {pmatrix} ^{50}_0 \end {pmatrix} (0.3372)^0 (1-0,3372)^{50} + \begin {pmatrix} ^{50}_1 \end {pmatrix} (0.3372)^1 (1-0,3372)^{49}  + \begin {pmatrix} ^{50}_2 \end {pmatrix} (0.3372)^2 (1-0,3372)^{48} +...  + \begin {pmatrix} ^{50}_{50{ \end {pmatrix} (0.3372)^{50} (1-0,3372)^{0}

P(Y ≥ 15) = 0.763

7 0
3 years ago
6= 2(y+2). Helppppppppppppppp
Licemer1 [7]

Answer:

y=1

Step-by-step explanation:

6=2y+4

2=2y

y=1

4 0
3 years ago
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