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Savatey [412]
3 years ago
8

Kyle incorrectly says that the product of - ( - 6 ) # ( - 1 ) is 6 . 11. After a recycling awareness program, the number of tons

of recyclable material taken to the landfill is reduced by 13 7 tons per 7 11 77 a. What is the correct product? 10 month. Represent the total change in the b. What was Kyle's likely error?
Mathematics
1 answer:
GaryK [48]3 years ago
8 0

Complete question:

Kyle incorrectly says that the product of - ( - 6 ) # ( - 1 ) is 6 . 11. After a recycling awareness program, the number of tons of recyclable material taken to the landfill is reduced by 13 7/10 tons per month. Represent the total change in the tons of recyclable material taken to the landfill after 7 months resulting from the awareness program a. What is the correct product? 10 month. Represent the total change in the b. What was Kyle's likely error?

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Kyle incorrectly says that the product of - ( - 6 ) ( - 1 ) is 6

-(-6)(-1) = 6 [incorrect]

Correction:

-(-6) (-1) :

- (-6) = 6

6 (-1) = - 6

Given that reduction in materials = 13 7/10 tons per month

Monthly reduction = 13 7/10 = 137/10 tons

After 7 months : (7 * 137/10) = 959/10 tons = 95.9 tons

Change in amount of material taken to the land fill:

Initial amount - amount after 7 months

If initial amount = x

Change in amonnt = (x - 95.9) tons

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Select the two figures that are similar to each other.
kakasveta [241]

Answer:

B and D

Step-by-step explanation:

if they had letters it would be

A     B

C     D

options B and D are similar

7 0
3 years ago
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What is the primary goal and secondary goal of the Fried Liver Opening in chess? <br />
polet [3.4K]

Play usually continues 7.Qf3+ Ke6 8.Nc3 (see diagram). Black will play 8...Nb4 or 8...Ne7 and follow up with c6, bolstering his pinned knight on d5. If Black plays 8...Nb4, White can force the b4 knight to abandon protection of the d5 knight with 9.a3?! Nxc2+ 10.Kd1 Nxa1 11.Nxd5, sacrificing a rook, but current analysis suggests that the alternatives 9.Qe4, 9.Bb3 and 9.O-O are stronger. White has a strong attack, but it has not been proven yet to be decisive.

Because defence is harder to play than attack in this variation when given short time limits, the Fried Liver is dangerous for Black in over-the-board play, if using a short time control. It is also especially effective against weaker players who may not be able to find the correct defences. Sometimes Black invites White to play the Fried Liver Attack in correspondence chess or in over-the-board games with longer time limits (or no time limit), as the relaxed pace affords Black a better opportunity to refute the White sacrifice.


3 0
3 years ago
Justo ayer fue el cumpleaños de Mauricio. Si a la edad e Mauricio, le sumo 13, al resultado le resto 10, luego al nuevo resultad
bezimeni [28]

Answer:

Mauricio nació en el año 2000.

Step-by-step explanation:

Supóngase que el cumpleaños se celebra en el año 2020, si x es la edad actual de Mauricio, entonces la expresión matemática que traduce el enunciado del problema es:

\frac{(x+13)-10}{23} +20 = 21

Ahora, se desarrolla y se simplifica la ecuación:

\frac{x+3}{23}+20 = 21

\frac{x+3}{23} = 1

Se despeja x:

x +3 = 23

x = 20

Mauricio tiene 20 años.

Ahora, el año de nacimiento de Mauricio es la sustracción de la edad de Mauricio del año actual:

y = 2020-20

y = 2000

Mauricio nació en el año 2000.

3 0
3 years ago
A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature
Westkost [7]

Answer:

(a) The value of <em>k</em> is \frac{1}{15}.

(b) The probability that at most three forms are required is 0.40.

(c) The probability that between two and four forms (inclusive) are required is 0.60.

(d)  P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 is not the pmf of <em>y</em>.

Step-by-step explanation:

The random variable <em>Y</em> is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of <em>k</em>.

\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}

Thus, the value of <em>k</em> is \frac{1}{15}.

(b)

Compute the value of P (Y ≤ 3) as follows:

P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\   =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 to be the pmf of Y it has to satisfy the conditions:

  1. P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\
  2. \sum P(y)=1

<u>Check condition 1:</u>

y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0

Condition 1 is fulfilled.

<u>Check condition 2:</u>

\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1

Condition 2 is not satisfied.

Thus, P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 is not the pmf of <em>y</em>.

7 0
3 years ago
There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is
shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, n(P) = 6

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Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}

Now, probability that both the picked caps are purple is given by their probability product. This gives,

P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33

Therefore, the probability that he picked 2 purpled socks is 0.33

4 0
3 years ago
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