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AlekseyPX
3 years ago
7

Will anyone please help me solve this physics Problem?​

Physics
1 answer:
ArbitrLikvidat [17]3 years ago
5 0

Answer:

I. Clockwise moment = 150 Nm

II. Anticlockwise moment = 400 Nm

III. 200 N

III. The anticlockwise moment.

Explanation:

From the question given above, we can obtain the answers to the questions as follow:

I. Determination of the clockwise moment.

Distance (d) = 1.5 m

Force (F) = 100 N

Clockwise Moment =?

Moment = Force × distance.

Clockwise moment = 100 × 1.5

Clockwise moment = 150 Nm

II. Determination of the anticlockwise moment.

Distance (d) = 2 m

Force (F) = 200 N

Anticlockwise Moment =?

Moment = Force × distance.

Anticlockwise moment = 200 × 2

Anticlockwise moment = 400 Nm

III. Determination of who will turn the sea saw.

Clockwise moment = 150 Nm

Anticlockwise moment = 400 Nm

Since the anticlockwise moment is greater than the clockwise moment, it therefore means that the anticlockwise moment will turn the sea saw.

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I can think of two possible and logical questions for the problem given. First, you can calculate for the maximum height reached by the blue ball. Second, you can compute the length of time for the two balls to be at the same height. If so, the solution are as follows:

When the object is thrown upwards or when the object is dropped from a height, the only force acting upon it is the gravitational force. Because of this, it simplifies equations of motion.

1. For the maximum height, the equation is
H = v₀²/2g
where
v₀ is the initial speed
g is the acceleration due to gravity equal to 9.81 m/s²

For the blue ball, v₀ = 21.8 m/s. Substituting the values:
H = (21.8 m/s)²/2(9.81m/s²)
H = 24.22 m
The maximum height reached by the blue ball is 24.22 m + 0.9 = 25.12 m.

2. For this, you equate the y values of both balls:

y for red ball = y for blue ball
v₀t + 0.5gt² = v₀t + 0.5gt²
(10.4 m/s)t + 0.5(9.81 m/s²)(t²) + 26.6 m = (21.8 m/s)t + 0.5(9.81 m/s²)(t²) + 0.9 m
Solving for t, 
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Thus, the two balls would be at the same height after 2.25 seconds.
3 0
4 years ago
Which of the following methods has led to the earliest discoveries of massive planets orbiting near their parent stars a. detect
Mrac [35]

Answer:

c. detecting the gravitational effect of an orbiting planet (The Wobble"") by looking for the Doppler shifts in the star's spectrum

Explanation:

In a solar system the mass of the star and planets affect each other's orbital  movements. The center of gravity of a star and a planet is inside the star. This causes the star to be closer and farther from the Earth at different times. Due to this wobble the star appears to be red shifted when it is farther and blue shifted when it is closer.

When the mass of the planet is high, like a hot Jupiter it causes more wobble i.e., change in radial velocity. This makes it easier to detect the planet. The earliest hot Jupiter found by this method is the planet 51 Pegasi b.

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Answer:

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7 0
3 years ago
I need help with these. Please show workings<br>​
Sauron [17]

Answer:

Imp = 25 [kg*m/s]

v₂= 20 [m/s]

Explanation:

In order to solve these problems, we must use the principle of conservation of linear momentum or momentum.

1)

(m_{1}*v_{1})+(F*t)=(m_{1}*v_{2})

where:

m₁ = mass of the object = 5 [kg]

v₁ = initial velocity = 0 (initially at rest)

F = force = 5 [N]

t = time = 5 [s]

v₂ = velocity after the momentum [m/s]

(5*0) +(5*5) = (m_{1}*v_{2}) = Imp\\Imp = 25 [kg*m/s]

2)

(m_{1}*v_{1})+(F*t)=(m_{1}*v_{2})\\(0.075*0)+(30*0.05)=(0.075*v_{2})\\v_{2}=20 [m/s]

8 0
3 years ago
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lubasha [3.4K]
Answer is A because the speed and velocity would change. Think of it as GTA, your going 30+ miles per hour and you take a left turn, the speed and velocity would change in an instant.. 
Hope this helped.
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3 years ago
Read 2 more answers
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