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3 years ago

7

a bus carrying a band and all their equipment has an initial velocity of 14 m/s. it accelerates for 3seconds

1 answer:

irga5000 [103]3 years ago

8 0

-- If the acceleration is positive, then the velocity of the bus
at the end of the 3 seconds is greater than 14 m/s.

-- If the acceleration is negative, then the velocity of the bus
at the end of the 3 seconds is less than 14 m/s, and may even
have reversed direction.

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A motorboat maintained a constant speed of 15 miles per hour relative to the water in going 10 miles upstream and then returning

Lesechka [4]

Answer:

speed of current is 5 mile/hr

Explanation:

GIVEN DATA:

speed of motorboat = 15 miles/hr relative with water

let c is speed of current

15-c is speed of boat at upstream

15+c is speed of boat at downstream

we know that

travel time=distance/speed

$\frac{10}{15-c} +\frac{10}{15+c} = 1.5$

150+10c+150-10c=1.5(15-c)(15+c)

300=1.5(225-c^2)

300=337.5-1.5c^2

200=225-c^2

c^2=25

c = 5

so speed of current is 5 mile/hr

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3 years ago

Is Li Chen abiotic or biotic?

kherson [118]

Answer:

abiotic

Explanation:

i think but dont take my word for it

8 0

4 years ago

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You lift a large bag of flour from the floor to a 2.5m high counter, doing 400J of work in 2 seconds. How much force did you app

oksian1 [2.3K]

<h2>The man have to apply force of 160 N</h2>

Explanation:

The work done to lift the bag of weight mg through height 2.5 m is 400 J

The work done can be found by relation W = mg x h

Thus mg = $\frac{W}{h}$ = $\frac{400}{2.5}$ = 160 N

Therefore the man have to apply the force of 160 N

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3 years ago

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A piston-cylinder device initially contains 0.08 m3 of nitrogen gas at 150 kPa and 200°C. The nitrogen is now expanded to a pres

Lemur [1.5K]

Answer:

$V_2 = 0.125 m^3$

Work done = = 5 kJ

Explanation:

Given data:

volume of nitrogen $v_1 = 0.08 m^3$

$P_1 = 150 kPa$

$T_1 = 200 degree celcius = 473 Kelvin$

$P_2 = 80 kPa$

Polytropic exponent n = 1.4

$\frac{T_2}{T_1} = [\frac{P_2}{P_1}]^{\frac{n-1}{n}$

putting all value

$\frac{T_2}{473} = [\frac{80}{150}]^{\frac{1.4-1}{1.4}$

$\frac{T_2} = 395.23 K = 122.08 DEGREE \ CELCIUS$

polytropic process is given as

$P_1 V_1^n = P_2 V_2^n$

$150\times 0.08^{1.4} = 80 \times V_2^{1.4}$

$V_2 = 0.125 m^3$

work done $= \frac{P_1 V_1 -P_2 V_2}{n-1}$

$= \frac{150 \times 0.8 - 80 \times 0.125}{1.4-1}$

= 5 kJ

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pentagon [3]

Answer:

Explanation:

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Exercise puts the spark back into your sex life. ...

Exercise can be fun … and social!

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3 years ago