Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:
The amount of deer that were initally in the reserve corresponds to the value of N when t=0
A. Initially, there were 12 deer.
B. 
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. 
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.
Answer:
<em> or 10.8627805 </em>
Step-by-step explanation:
Start by taking the difference of each value of both points
<u>Find the difference in x values </u>
78-2 = 76
<u>Find the difference in y values</u>
46-4 = 42
<u>Add the two differences </u>
76+42=118
<u>Take the square root of this value </u>
<u /><u />
Answer:
21
Step-by-step explanation:
bc
1
12
9
+--
21
Answer:
Company A: 
Company B: 
Step-by-step explanation:
The initial fee is the y-intercept, as that is the cost at x = 0, or the cost before any time has passed. Afterwards, the rate the cost increases is the slope.
Linear equation in slope-intercept form:
where m is the slope and b is the y-intercept.
Company A charges $50 up front and $40 per hour afterwards, so the equation would be:
Company B charges $25 up front and $50 per hour, so:
