Hello from MrBillDoesMath!
Answer:
58
Discussion:
Suppose the 2-digit number is "ab". That is, 10a + b.
Sum of digits = 13 => a + b = 13 (*)
Digits reversed if 27 added to number => (10a + b) + 27 = 10b + a (**)
(**) =
(10a + b) + 27 = 10b + a => subtract 10b, then a, from both sides
9a -9b = -27 => divide both sides by 9
a - b = -3
From (*), a+ b = 13 so
(a-b) + ( a+b) = -3 + 13 =>
2a = 10 =>
a = 5
As a +b = 13, 5 + b = 13 => b = 8
Hence the number "ab" is 58
Thank you,
MrB
7/8 minus1/4 minus 1/2
7/8 - 1/4 - 1/2 =
(1 × 7)/(1 × 8) - (2 × 1)/(2 × 4) - (4 × 1)/(4 × 2) =
7/8 - 2/8 - 4/8 =
(7 - 2 - 4)/8 =
1/8
the answer is 1/8
Answer:
Null hypothesis; H0: µ ≥ 52 mpg
Alternative hypothesis; Ha: µ < 52 mpg
Step-by-step explanation:
We are told that the newest model gets an average of 52 miles per gallon and that the buyers believe that the average mpg was overstated.
This means the alternative hypothesis will have an average less than 52. Thus;
Null hypothesis; H0: µ ≥ 52 mpg
Alternative hypothesis; Ha: µ < 52 mpg
Answer: 57.27
Step-by-step explanation:
using the proportion we have x= (5*126)/11= 57.27
1. What’s the probablity of a second person winning the small prize?
There are now 99 total marbles, and 24 silver marbles. So, 24/99 is 0.24 probability.
2. Which player is most likely to win a big prize?
Since each player draws a silver marble (aka a small prize) there are less small prize marbles in the bag after each turn. So, the first person would have a 5% chance (or 0.05)of winning the big prize gold marble, but the last person would have a slightly bigger chance (5.15% or 0.0515) of winning a big prize.
3. How could the game be made fair for each player?
Well it’s quite simple, just have each player return their marble and the number of marbles would be kept constant, giving everyone an equal chance. Or you could have them all play at the same time, either way.
4. Same answer as 3
