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Elenna [48]
3 years ago
11

Find the value of x and y

Mathematics
1 answer:
NISA [10]3 years ago
3 0
The answer is C. For sure
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A kayaker can paddle 12 mi in 2 h moving with the river current. Paddling at the same pace, the trip back against takes 4 h. Ass
Firdavs [7]
Downstream DATA:
distance = 12 miles 
time = 2 hours 
rate = 12/2 = 6 mph
----------------
Upstream DATA:
distance = 12 miles 
time = 4 hrs 
rate = 12/4 = 3 mph
----
Equations:
Downstream: b + c = 6
Upstream::: b - c = 3
------
Add to get:
2b = 9
b = 4.5 mph (speed of the boat in still water.)
-----
Solve for "c":
b + c = 6
4.5 + c = 6
c = 1.5 mph (speed of the current)
The answer is 1.5 mph
7 0
3 years ago
Please help me on this question.
zimovet [89]
One over 3
Three over 4 1/2
Two over 5 
One over 5 1/2
hope it helped :33
3 0
4 years ago
Read 2 more answers
Consider a finite population with five elements labeled A, B, C, D, and E. Ten possible simple random samples of size 3 can be s
ASHA 777 [7]

Answer:

10% probability that each sample of size 3 is selected

Step-by-step explanation:

Each sample has the same probability of being selected.

There are 10 samples.

This means that the probability of each sample being selected is:

1/10 = 0.1

10% probability that each sample of size 3 is selected

6 0
4 years ago
Find the diamter of a circle if its area is 706.9mm²​
Masteriza [31]

Answer:

<h2>30 mm</h2>

Step-by-step explanation:

The formula of an area of a circle:

A=\pi r^2

<em>r</em><em> - radius</em>

<em />

We have

A=706.9\ mm^2

Substitute:

\pi r^2=706.9          <em>divide both sides by π</em>

r^2=\dfrac{706.9}{\pi}        <em>use π ≈ 3.14</em>

r^2\approx\dfrac{706.9}{3.14}\\\\r^2\approx225\to r=\sqrt{225}\\\\r= 15\ mm

The diameter <em>d = 2r</em>.

Therefore

d=2(15)=30\ mm

3 0
3 years ago
Paul walks 25 feet away from his house and places a mirror on the ground. He backs 5 feet away from the mirror so that he can se
blagie [28]

Answer:

The height of the house is 30 feet

Step-by-step explanation:

* Lets explain how to solve the problem

- Name the place of the mirror with M

- Name the place of Paul with P

∴ MP is the distance between Paul and the mirror

∵ The distance between Paul and the mirror is 5 feet

∴ MP = 5

- Name the place of Paul's eyes with E

- Name the tip of the roof with T

∴ MET is a line segment

- Name the place of the house on the ground with H

- The line TH represent the height of the house

∴ TH = the height of the house

- The line HM is the distance between the house and the mirror

∵ The distance between the house and the mirror is 25 feet

∴ HM = 25

- Paul and the house are both perpendicular to the ground

∴ TH and EP ⊥ HM at H and E

∴ TH // EP

- Paul's eyes are 6 feet above the ground

∴ EP = 6

- All these situations represent two triangles THM and EPM

- Δ THM represents the house , the tip of the roof and the mirror

- Δ EPM represents Paul's eyes , Paul position and the mirror

- In Δ THM

∵ TH // EP

∴ m∠ THM = m∠ EPM ⇒ alternate angles

∴ m∠ HTM = m∠ PEM ⇒ alternate angles

∴ Δ THM ≈ Δ EPM ⇒ AA similarity

∴ EP/TH = MP/MH

∵ EP = 6 , MP = 5 , MH = 25

∴ 6/TH = 5/25 ⇒ by using cross multiplication

∴ 5 TH = 6 × 25

∴ 5 TH = 150 ⇒ divide both sides by 5

∴ TH = 30

- TH is the height of the house

* The height of the house is 30 feet

7 0
4 years ago
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