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tino4ka555 [31]
2 years ago
12

7^10 is _____ times larger than 7^8.

Mathematics
1 answer:
dalvyx [7]2 years ago
7 0

Answer:

2 times greater

Step-by-step explanation: since 10 subtracted by 8 is 2

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The perimeter of the triangle below is 97 cm.
Sloan [31]

Answer:

The length of EF = x = 18 cm

Option A is correct.

Step-by-step explanation:

Ware given perimeter of triangle = 97 cm

We need to find length of EF = x = ?

The length of EG = x+7

The length of EF = x

The length of GF = 3x

The formula used is: Periemter \ of \ triangle= Sum \ of \ all \ sides \ of \ triangle

Putting values and finding x i.e length of EF

Periemter \ of \ triangle= Sum \ of \ all \ sides \ of \ triangle\\97=x+7+x+3x\\97-7=5x\\5x=90\\x=\frac{90}{5}\\x=18 \ cm

So, value of x=18 cm

The length of EF = x = 18 cm

Option A is correct.

4 0
3 years ago
Stanley is having trouble understanding how to find the GCF
soldier1979 [14.2K]

Answer:

8

Step-by-step explanation:

All the factors of 8 and 16 are 1;2;4;8

3 0
3 years ago
Help please uh thanks
Triss [41]
12•1
13•6
12/78 divide both numbers by 6 to simplify
Answer- 2/13
6 0
2 years ago
Read 2 more answers
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
3 years ago
The density of an object can be found by taking its mass and dividing by its volume write an equation to represent the relations
lukranit [14]
The density of an object is what i can’t see the question
4 0
3 years ago
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