Question

In triangle RST the vertices have coordinates of R(-1,10),S(5,4)and T (-4,-2). If the midpoints of side RS and RT were connected with a segment, what would the slope of this segment be?
Plz helppp

Answer 1

Answer:

$\frac{2}{3}$

Step-by-step explanation:

Midpoint of a line segment joining points $(x,y)$ and $(u,v)$ is given by $(\frac{x+u}{2},\frac{y+v}{2} )$

Points are R(-1,10),S(5,4)and T (-4,-2).

Midpoint of RS = $(\frac{-1+5}{2},\frac{10+4}{2} )=(\frac{4}{2},\frac{14}{2} )=(2,7 )$

Midpoint of RT = $(\frac{-1-4}{2},\frac{10-2}{2} )=(\frac{-5}{2},\frac{8}{2} )=(\frac{-5}{2},4)$

Slope of a line joining points $(a,b)$ and $(c,d)$ is given by $\frac{d-b}{c-a}$

Slope of line joining midpoints of side RS and RT = $(\frac{4-7}{\frac{-5}{2}-2 })=(\frac{-3}{\frac{-9}{2} })=\frac{2}{3}$