Answer:
The correct answer will be- 200
Explanation:
The cell cycle in eukaryotes mostly takes place in four phases: G₁, S, G₂ and M phase in sequence.
The DNA replication takes place during S phase which doubles the amount of DNA in a cell after which during M- phase the DNA divides into the daughter cell.
The amount of DNA present during G₂ phase is the 200 pg which will remain same until anaphase I as the segregation of chromosomes to the daughter cells takes place in the anaphase. Therefore, the amount of DNA observed after G₂ phase will remain 200 pg till metaphase I.
Thus, 200 is the correct answer.
Answer:
How to Save the Rainforest
Teach others about the importance of theenvironment and how they can help save rainforests.
Restore damaged ecosystems by planting trees on land where forests have been cut down.
Encourage people to live in a way that doesn't hurt the environment.
Establish parks to protect rainforests and wildlife.
39
Reproductive cells are haploid (have 1/2 the chromosomes), whereas somatic/body cells are diploid (have the full set of chromosomes)
This makes sense if you think about it. Using the example from the question, every dog has 78 chromosomes. This includes two of each (there are two chromosome 1's, two chromosome 2's, etc. This is visible in the karyotype attached). One set of these chromosomes were inherited from the mother, and one set from the father. Each parent contributed 39 chromosomes (one chromosome 1, one chromosome 2, etc.). If the dog in the question were to have 78 chromosomes in its sperm cells, it would contribute two sets to its offspring. When combined with the chromosomes in the egg cell, the offspring would end up with extra chromosomes. Therefore, both the sperm and the egg cells will have 39 chromosomes, one of each. When combined, they will produce offspring with 78 chromosomes, the proper number.