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2 answers:
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I remember dis, yey
so if a polynomial has roots
, 
, 
, it can be factored into
where a,b,c,d are constants
also, if a polynomial has rational coefients and a+bi is a root, then a-bi must also be a root
so our roots we need are
4,16, 1+9i and 1-9i
so assuming multiplity 1 (that means we have something like [/tex]f(x)=a(x-r_1)^1(x-r_2)^1(x-r_3)^1[/tex])
we get that your function is
which simplifies to
which expands to
so if a polynomial has roots
also, if a polynomial has rational coefients and a+bi is a root, then a-bi must also be a root
so our roots we need are
4,16, 1+9i and 1-9i
so assuming multiplity 1 (that means we have something like [/tex]f(x)=a(x-r_1)^1(x-r_2)^1(x-r_3)^1[/tex])
we get that your function is
Problem 1
We'll use the product rule to say
h(x) = f(x)*g(x)
h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)
Then plug in x = 2 and use the table to fill in the rest
h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)
h ' (2) = f ' (2)*g(2) + f(2)*g ' (2)
h ' (2) = 2*3 + 2*4
h ' (2) = 6 + 8
h ' (2) = 14
<h3>Answer: 14</h3>============================================================
Problem 2
Now we'll use the quotient rule
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Problem 3
Use the chain rule