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Neko [114]
3 years ago
12

Solve for x if 2(5x + 2)^2 = 48

Mathematics
2 answers:
Sophie [7]3 years ago
8 0
Distribute=2(5x+2) and 2(5x(5x+2)+2(5x+2))

Distribute
2
(
2
5

2
+
1
0

+
2
(
5

+
2
)
)
2
(
25
x
2
+
10
x
+
2
(
5
x
+
2
)
)
2
(
2
5

2
+
1
0

+
1
0

+
4
)



Combine like terms
2
(
2
5

2
+
1
0

+
1
0

+
4
)
2
(
25
x
2
+
10
x
+
10
x
+
4
)
2
(
2
5

2
+
2
0

+
4
)
attashe74 [19]3 years ago
3 0
I think x= 3.2 but who knows i’m not that good at math
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The rectangle shown is dilated by a scale factor of 3.
Law Incorporation [45]
Given that the image was dilated by scale factor 3 then:
a] Length of the dilated side will be:
length/width=(original length/width)*(scale factor)
length=3*10=30 in
Width=3*6=18 in
thus the dimensions of the new image will be:
30 in by 18 in

b. The diagram below represent s the rectangle. 1 cm represent 10 inches

7 0
3 years ago
Which situation shows a constant rate of change? A. The number of points scored in a basketball game compared with the number of
bezimeni [28]

Answer: D

Step-by-step explanation:

A constant rate of change means that for every x, y increases the same amount.

In the situation "The amount a person pays for gas compared with the number of gallons purchased ," the independent quantity, or x-value, is the number of gallons, and the dependent quantity, or y-value, is the amount paid.  Since gas has a set price per gallon, for every gallon purchased, the total amount paid goes up the same amount.  This means it has a constant rate of change.

8 0
3 years ago
Find the probability of getting four consecutive aces when four cards are drawn without replacement from a standard deck of 52 p
posledela

Answer:

<em>P=0.0000037</em>

<em>P=0.00037%</em>

Step-by-step explanation:

<u>Probability</u>

A standard deck of 52 playing cards has 4 aces.

The probability of getting one of those aces is

\displaystyle \frac{4}{52}=\frac{1}{13}

Now we got an ace, there are 3 more aces out of 51 cards.

The probability of getting one of those aces is

\displaystyle \frac{3}{51}=\frac{1}{17}

Now we have 2 aces out of 50 cards.

The probability of getting one of those aces is

\displaystyle \frac{2}{50}=\frac{1}{25}

Finally, the probability of getting the remaining ace out of the 49 cards is:

\displaystyle \frac{1}{49}

The probability of getting the four consecutive aces is the product of the above-calculated probabilities:

\displaystyle P= \frac{1}{13}\cdot\frac{1}{17}\cdot\frac{1}{27}\cdot\frac{1}{49}

\displaystyle P= \frac{1}{270,725}

P=0.0000037

P=0.00037%

3 0
3 years ago
Find the missing side of the triangle !!!<br> HELP MEEE!!!!!!!!!!!!!!
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The answer would be 10

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3 years ago
Angle 1 measure 75 degree what is its complement
dalvyx [7]
I think it’s 76 because I added it that’s a way i solved it but you can also multiple it by 1 and it will give the the same answer
3 0
3 years ago
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