Okay, it's the equation to how find area any other way. A=L×W

This means *picture above*

So then you count over each line meaning 1.
This means L=9 and a 1/2. Since its in between the 2 an 3 on the x-axis.
Now for W or width. It equals 3 since you can count 2 lines and one either ends of the polygon is 1/2 each this creates one when added together.

All you do from there is multiply 9 and 3. This should give you A=area.

8 0

3 years ago

HELP ASAP 10 POINTS TO BRAINLIEST

Brilliant_brown [7]

Answer:

15%

Step-by-step explanation:

The cost of 2 adults and 2 children without the discount is

2 adults = 2 (55) = 110

2 children = 2 (45) = 90

Total cost = 110+90 = 200

The original price is 200 and the new price is 170

Percentage discount = (Original price - new price)/ original price * 100%

= (200-170)/200 * 100%

= 30/200 * 100%

= .15 * 100%

= 15%

6 0

3 years ago

Two altitudes of a triangle have lengths $12$ and $14$. What is the longest possible integer length of the third altitude

nataly862011 [7]

The longest possible altitude of the third altitude (if it is a positive integer) is 83.

According to statement

Let h is the length of third altitude

Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.

From Area of triangle

A = 1/2*B*H

Substitute the values in it

A = 1/2*a*12

a = 2A / 12 -(1)

Then

A = 1/2*b*14

b = 2A / 14 -(2)

Then

A = 1/2*c*h

c = 2A / h -(3)

Now, we will use the triangle inequalities:

a < b+c

2A/12 < 2A/14 + 2A/h

Solve it and get

h<84

b < a+c

2A/14 < 2A/12 + 2A/h

Solve it and get

h > -84

c < a+b

2A/h < 2A/12 + 2A/14

Solve it and get

h > 6.46

From all the three inequalities we get:

6.46<h<84

So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.

Learn more about TRIANGLE here brainly.com/question/2217700

#SPJ4

8 0

2 years ago

What is the perimeter of 6*4

Diano4ka-milaya [45]

24 would be the answer if its wrong i am so sorry but it has to be right

6 0

3 years ago