Ask question

Ask question

All categories

3 years ago

9

Magnesium and iron are metallic elements. How does a mole of magnesium compare with a mole of iron?Which value gives the number

of particles in 1 mol of a substance?

1 answer:

scZoUnD [109]3 years ago

3 0

Answer:

They both have the same number of atoms.

Explanation:

You might be interested in

Which of the following describes the degree to which molecules of one substance are attracted to the molecules of another substa

Arada [10]

The answer is adhesion

5 0

4 years ago

Read 2 more answers

Why is one able to walk on red-hot coals without getting one’s feet burned?

Hunter-Best [27]

Before the person walks through burning coal, the person will make sure their feet are very wet. When they start walking on the coal, the moisture will evaporate and form a protective gas layer underneath the person's feet.

You can see examples of this if you happen to drip some water on a hot stove or any hot surface. The water will easily glide around on top of a newly formed layer of air underneath it, like air hockey pucks on an air hockey table.

3 0

3 years ago

Select the correct answer.<br> What happens as you decrease the temperature of a solution?

shepuryov [24]

Answer:

the number of solute particles increases

3 0

3 years ago

HELP PLEASE!!!!!!!!! What if you started with 100 grams of wood and only have 95 grams of ashes produced, is mass still conserve

Lerok [7]

My guess is smoke. Smoke is matter.

7 0

3 years ago

The Ka of hydrazoic acid (HN3) is 1.9 × 10-5 at 25.0 °C. What is the pH of a 0.40 M aqueous solution of HN3?

siniylev [52]

Answer:

The pH of the solution is 2.56.

Explanation:

Given :

Concentration (c) = 0.40 M

Acid dissociation constant = $K_a=1.9\times 10^{-5}$

The equilibrium reaction for dissociation of $HN_3$ (weak acid) is,

$HN_3+H_2O\rightleftharpoons N_3^{-}+H_3O^+$

initially conc. c 0 0

At eqm. $c(1-\alpha)$ $c\alpha$ $c\alpha$

Dissociation constant is given as:

$K_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}$

$1.9\times 10^{-5}=\frac{(0.40\alpha)(0.40\alpha)}{0.40(1-\alpha)}$

By solving the terms, we get value of $(\alpha)}$

$\alpha=0.00686832$

No we have to calculate the concentration of hydronium ion or hydrogen ion.

$[H^+]=c\alpha=0.4\times 0.00686832=0.002747 M$

Now we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (0.002747)$

$pH=2.56$

Therefore, the pH of the solution is, 2.56.

8 0

4 years ago