KBr + H2O = KOH + Br2 + H2
So we know that we need a 2 on the left of kbr so it would equal the right Br.
=2KBr
now put a 2 in front of KOH since we need a 2k on right side
Now we put a 2 infront of H2O which wil make 4 h's and 2 o's
2h2o
now it is balanced
2KBr + 2H2O = 2KOH + Br2 + H2
Answer:
94.1 %
Explanation:
We firstly determine the equation:
2H₂O + O₂ → 2H₂O₂
2 moles of water react to 1 mol of oxygen in order to produce 2 moles of oxygen peroxide.
We convert the mass of oxygen to moles:50 g . 1mol /32g = 1.56 mol
Certainly oxygen is the limiting reactant.
2 moles of water react to 1 mol of oxygen.
13 moles of water may react to 13/2 = 6.5 moles. (And we only have 1.56)
As we determine the limiting reactant we continue to the products:
1 mol of O₂ can produce 2 moles of H₂O₂
Then 1.56 moles of O₂ will produce (1.56 . 2) = 3.125 moles
We convert the moles to mass: 3.125 mol . 34 g/mol= 106.25 g
That's the 100% yield or it can be called theoretical yield.
Percent yield = (Yield produced / Theoretical yield) . 100
(100g / 106.25 g) . 100 = 94.1 %
It is b or a check with someone else
The most abundant alkali metal is *Sodium*
