All categories

3 years ago

Which equation has x = –6 as the solution?

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

3 0

Answer:

The equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e. $\log _3\left(-2x-3\right)=2$ has x = –6 as the solution.

Step-by-step explanation:

Checking the equation

log Subscript 3 Baseline (negative 2 x minus 3) = 2

Writing in algebraic expression

$\log _3\left(-2x-3\right)=2$

Use the logarithmic definition

$\mathrm{If}\:\log _a\left(b\right)=c\:\mathrm{then}\:b=a^c$

$\log _3\left(-2x-3\right)=2\quad \Rightarrow \quad \:-2x-3=3^2$

$-2x-3=3^2$

$-2x-3=9$

$-2x=12$

$\mathrm{Divide\:both\:sides\:by\:}-2$

$\frac{-2x}{-2}=\frac{12}{-2}$

$x=-6$

Therefore, the equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e. $\log _3\left(-2x-3\right)=2$ has x = –6 as the solution.

KonstantinChe [14]3 years ago

3 0

Answer:

(-2x-3)=2

Step-by-step explanation:

You might be interested in

I need help with this math question pretty please

AleksAgata [21]

Just do 11x18x20x14 and u should get it

3 0

3 years ago

Read 2 more answers

Anna had $54 in her purse. She bought a book for $26.34 and a book marker for $1.27. Anna’s mom then gave her $10 for completing

jekas [21]

Answer:

Anna has $36.39 dollars.

Step-by-step explanation:

All we have to do is subtract

54 - (26.34 + 1.27) =

54 - 27.61 =

36.39

So, the answer is 36.39

Hope this helps! :)

3 0

2 years ago

Read 2 more answers

If you're good at trig pls help meeeeee and show full working out pls

saveliy_v [14]

Answer:

19 km

Step by step explanation:

6 0

3 years ago

If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

nikklg [1K]

The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.