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SCORPION-xisa [38]
3 years ago
6

What is the interrelation among work, energy and power? ​

Physics
1 answer:
DochEvi [55]3 years ago
8 0

Answer:

Work, energy and power are inter-related and interdependent. Let's see how, Work- Energy is needed for work. Power- It is the effectiveness of doing work. It is the rate of doing work. Energy- It is the capacity or potential to work.

Thank you

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rank the following media from fastest to slowest for a light wave to travel through 1 being fastest 4 being slowest ( a. gas, b.
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The answer should be B. Solid

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Which is a vector quantity
Korolek [52]

Explanation:

Physical quantities are usually designated as either vector or scalar quantities.

There are several fundamental quantities know out there that makes definition of the world possible. Derived quantities are obtained from these fundamental quantities.

  • A vector quantity expresses a quantity that shows both magnitude and direction.
  • With a vector, you know the amount or quantity of measurement taken and the directional attribute.
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learn more:

Vector brainly.com/question/2678571

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4 0
3 years ago
The average human hair has a diameter of 100,000 nm. We can see individual hairs because hair has a diameter greater than the wa
sertanlavr [38]

B is the correct answer, since all others are not true or are based on assumption

6 0
3 years ago
Air enters a turbine operating at steady state at 8 bar, 1400 K and expands to 0.8 bar. The turbine is well insulated, and kinet
vladimir2022 [97]

To solve this problem it is necessary to apply the concepts related to the adiabatic process that relate the temperature and pressure variables

Mathematically this can be determined as

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

Where

T_1 =Temperature at inlet of turbine

T_2 = Temperature at exit of turbine

P_1 = Pressure at exit of turbine

P_2 =Pressure at exit of turbine

The steady flow Energy equation for an open system is given as follows:

m_i = m_0 = m

m(h_i+\frac{V_i^2}{2}+gZ_i)+Q = m(h_0+\frac{V_0^2}{2}+gZ_0)+W

Where,

m = mass

m_i = mass at inlet

m_0= Mass at outlet

h_i = Enthalpy at inlet

h_0 = Enthalpy at outlet

W = Work done

Q = Heat transferred

V_i = Velocity at inlet

V_0= Velocity at outlet

Z_i= Height at inlet

Z_0= Height at outlet

For the insulated system with neglecting kinetic and potential energy effects

h_i = h_0 + W

W = h_i -h_0

Using the relation T-P we can find the final temperature:

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

\frac{T_2}{1400K} = (\frac{0.8bar}{8nar})^{(\frac{1.4-1}{1.4})}

T_2 = 725.126K

From this point we can find the work done using the value of the specific heat of the air that is 1,005kJ / kgK

So:

W = h_i -h_0

W = C_p (T_1-T_2)

W = 1.005(1400-725.126)

W = 678.248kJ/Kg

Therefore the maximum theoretical work that could be developed by the turbine is 678.248kJ/kg

5 0
4 years ago
The attractive or repulsive force between objects is called
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The answer to this is electric force. Hope it helps
3 0
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