The magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s
The rotating equivalent of linear momentum in physics is called angular momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is significant in physics. Both the direction and the amplitude of angular momentum are preserved.
Given the density of air to be 1.29 kg/m3 and a wind speed of 73.0 mi/h
We have to find the magnitude of the angular momentum
Let,
ρ = Density of air = 1.29 kg/m^3
v = Speed of wind = 73.0 mi/h = 0.032 km/s
M = angular momentum of air
Let the volume of air be 1 m^3
Mass = Volume x ρ = 1 x 1.29 = 1.29 kg
Momentum = M = mass x velocity
Momentum = 1.29 x 0.0032
Momentum = 4.128 x 10^(-3) kg·m^2/s
Hence the magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s
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<u>C</u> is the correct answer, because energy cannot be created neither destroy. The energy is changing from chemical to from electric to light, and from light to heat.
Answer: this one is tough. There is a estimated 1.2 billion drivers to help best I could. I did the math the best I could and didn’t get an answer close to the choices. Just guessing I’d guess C. 20,000 because of logic.
Explanation: I can’t help much but would love to hear how to work this out.
Answer:
101201.2 Pascal.
Explanation:
Given that the difference h between the two liquid levels is 2.0 cm. The density of the liquid is 800 kg /m3.
Calculate the difference between the pressure of the gas and atmospheric
pressure.
The pressure of the gas can be calculated by using the formula
Pressure = density × acceleration due to gravity × height
Substitute all the parameters into the formula
Pressure = 800 × 2/100 × 9.8
Note that the height is converted to metre.
Pressure = 156.8 Pascal
pressure difference = 101358 - 156.8
Pressure difference = 101201.2 Pascal
Yes it would be the same your weight would change:)
