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Sophie [7]
3 years ago
12

(4x-25) help quickly pls

Mathematics
2 answers:
MaRussiya [10]3 years ago
6 0

Answer:

ofc! it's  -100

Step-by-step explanation:

Hope this helps! God Bless you!!!

Oduvanchick [21]3 years ago
4 0

Answer: 4x-25 is the answer

Step-by-step explanation:

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Help, I don’t understand
Agata [3.3K]

Answer: -1

Step-by-step explanation: f(x) is another way of saying y. So when y is 3, according to the table, x is -1

3 0
2 years ago
What’s the answer to this? Find 1/8 of 88
guapka [62]

Answer:

11

Step-by-step explanation:

\frac{1}{8} of 88

= \frac{88}{8}

= 11

8 0
2 years ago
Read 2 more answers
to cover a rectangular region of her yard penny needs at least 170.5 square feet of sod. the length of the region is 15.5 feet.
pshichka [43]
To cover at least 170.5 sq.ft. the width must be at least 11 feet
W=170.5sq.ft / 15.5 ft = 11ft
7 0
3 years ago
Isosceles triangle SIX has congruent sides SI and IX and vertices S at (x, 5) , / at (- 2, 2) , and X at (4, - 1) , where x >
bazaltina [42]

Answer:

Isosceles triangles have two sides with the same length, and one side that ... Similarly, if two angles of a triangle have equal measure, then the sides ... (2) Set up an equation and solve for x. ... x = 60/2 x = 30. Each base angle of triangle ABC measures 30 degrees. ... In isosceles triangle RST, angle S is the vertex angle.

Step-by-step explanation:

8 0
3 years ago
Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
x=9-6 \sqrt{2}=0.5147

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
6 0
3 years ago
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