Somebody please help me answer this
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When a function intersects with the x-axis, it's y value must be 0. That means when the straight line intersects with the axis, it's at the point (4k,0), so plugging those numbers into our original equation yields:
Given equation of the Circle is ,
And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,
Here we can say that ,
• Radius = 5 units
• Centre = (0,0)
Finding distance between the two points :-
Here we can see that the distance of point from centre is less than the radius.
Hence the point lies within the circle .