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RideAnS [48]
4 years ago
7

5 (x + 2) = 3 (x + 8)

Mathematics
2 answers:
aleksley [76]4 years ago
8 0
So first you distribute the 5 to the x and the +2 and get
5x+10=3(x+8)
 then you distribute the 3 to the other x and the +8 and get
5x+10=3x+24
subtract 3x from both sides
2x+10=24
subtract 10 from both sides and get
2x=14
divide both sides by 2 and get
x=7
marin [14]4 years ago
7 0
5(x+2)=3(x+8)\ \ \ \ \ |simplify\\\\5x+10=3x+24\ \ \ \ \ \ |combine\ like\ terms\\\\5x-3x=24-10\\\\2x=14\ \ \ \ |:2\\\\x=7
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The function h (x) = StartFraction 1 Over x squared + 1 EndFraction is the result of the composition f(g(x)). If g(x) = x2 + 1,
dem82 [27]

Answer: 1/x

Step-by-step explanation:

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3 years ago
A miner descended 1100 feet into a mine. While in the mine, he then rose 950 feet and then descended 450 feet. What was the mine
Nostrana [21]
-600 feet because you do -1100+950-450
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Raymond built a “rocket" made from a cylinder and a cone. He filled the rocket
lianna [129]

Answer:

Rocket can hold maximum 4.5 gallons of water.

Step-by-step explanation:

Volume of the rocket = Volume of the cone on the top + Volume of the cylinder at the bottom

Volume of the cone = \frac{1}{3}\pi r^{2}h

Here r = radius of the circular base

h = height of the cone

Volume = \frac{1}{3}\pi (4)^{2}(14)

             = \frac{224\pi }{3} cubic inch

Volume of the cylinder = \pi r^{2}h

Here r = radius of the base

h = height of the cylinder

Volume = \pi (4)^{2}(16)

             = 256π cubic inches

Volume of the rocket = \frac{224\pi }{3}+256\pi

                                   = \frac{992\pi }{3}

                                   = 1038.82 cubic inches

Since 231 cubic inches volume of a rocket can hold water = 1 gallon

Therefore, 1038.82 cubic inches space can hold water

= \frac{1038.82}{231}

= 4.497

≈ 4.5 gallons

Rocket can hold 4.5 gallons of water.

7 0
3 years ago
True or False.<br><br> The expressions 4(y−3) and 4y−12 are equivalent?
pickupchik [31]

Answer:

true

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7 0
3 years ago
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A bag of sand originally weighing 144 lb is lifted at a constant rate. As it rises, sand also leaks out at a constant rate. At t
frosja888 [35]

Answer:

Step-by-step explanation:

The bag of sand wave is

W=144lb at x=0

The bag of sand is lifted at a constant rate, i.e the it is not accelerating, so a=0m/s²

Let W be the mass of the sand,

Sand leaks out at a constant rate

dW/dx= C

At a height=18ft, half of the original mass.

i.e x=18ft, M=72lb

We are asked to find the work at 18ft

Work is given as

Work=∫F•dx,

Where F is the force and also the weight of the sand, F=W

The Weight of the bag is a linear function,

dW/dx= C

Then, using variable separation

dW=Cdx

Integrating both sides

∫dW=∫Cdt

W=Cx + B

So, at x=0, W=144

144=B

B=144

W=Cx+144

Also at x=18, W=72lb

72=C×18+144

72-144=18C

-72=18C

C=-4

Then, the weight function becomes

W=-4x+144

W=144-4x

Then applying work formula

Work=∫W•dx

Work=∫(144-4x)dx. x=0 to x=18

Work = 144x-4x²/2. x=0 to x=18

Work=144x-2x² x=0 to x=18

Work=144(18)-2(18²) -0 -0

Work =2592-648

Work =1944 ft lbs

The work done in lifting the sand to 18ft is 1944 ft lbs

7 0
3 years ago
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