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Oksanka [162]
3 years ago
5

Cars A and B leave the same place and travel in the same direction along a straight road. Car A travels at 60 km/h and car B tra

vels at 72 km/h. After how long will they be at 8km apart?
Mathematics
2 answers:
marissa [1.9K]3 years ago
5 0

Answer:

Car A: 8 minutes

Car B: 6.67 minutes

Step-by-step explanation:

Car A: 60km evrery hour so,

1 km every minute, so he will be in 8km in 8 minutes.

Car B: 72km per hour so,

72/60 = 1.2 = 1.2 km per minute.

8/1.2 = 6.6666666666667 which is about 6.67 to the nearest hundredth.

yaroslaw [1]3 years ago
5 0

Answer:

40 min

Step-by-step explanation:

Car A is traveling at 1 km/min (60/60)

Car B is traveling at 1.2 km/min (72/60)

Car B gains .2km on Car A for every minute they drive.

8km/.2 = 40

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  1. an ace or a king  = 0.1538
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<u>Step-by-step explanation:</u>

Here we have , A card is drawn at random from a deck of 52 playing cards. We need to find that Find the probability that the card drawn is:

  • an ace or a king

A deck of standard 52 cards contain four aces. There are four kings in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}

⇒ probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}

⇒ probability = \frac{8}{52}

⇒ probability = 0.1538

  • a king or a diamond

A deck of standard 52 cards contain four kings. There are 13 Diamonds in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}

⇒ probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}

⇒ probability = \frac{(13+4=17)}{52}

⇒ probability = \frac{(17)}{52}

⇒ probability =0.3269

Therefore, probability that the card drawn is:

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