2 years ago

Find and sketch the domain of the function. f(x,y)=√(4-x^2-y^2) +√(1-x^2)

Mathematics

1 answer:

elena55 [62]2 years ago

3 0

Answer:

Hello

Step-by-step explanation:

The domain is limited with 2 lines parallel: -1 ≤ x ≤ 1

and the disk ? (inside of a circle) of center (0,0) and radius 2

$dom\ f(x,y)=\{(x,y) \in \mathbb{R} ^2 | \ -1\leq x \leq -1\ and \ ( -\sqrt{4-x^2} \leq \ y \leq \sqrt{4-x^2}\ ) \ \}\\$

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Find and sketch the domain of the function. f(x,y)=√(4-x^2-y^2) +√(1-x^2)​

Find and sketch the domain of the function. f(x,y)=√(4-x^2-y^2) +√(1-x^2)