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sveticcg [70]
3 years ago
8

Hi! 8th grade math problem for you. Please see the screenshot

Mathematics
1 answer:
deff fn [24]3 years ago
4 0

Answer:

r=4/2=2cm

total volume=volume of cylinder + cone=πr²h+1/3πr²h'=πr²(h+1/3 h')=2²π((10-3)+1/3× 3)=4π(7+1)=8×4π=32πcm³

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Help please please <br> $)
mart [117]
<h3>Look at the picture.</h3>

<em>commutative property</em>  a + b = b + a

... (-5 + 1/2 + 5) = ... (-5 + 5 + 1/2)

<em>inverse property of addition</em> a + (-a) = a - a = 0

... (-5 + 5 + 1/2) = ... (0 + 1/2)

<em>identity property of addition</em> a + 0 = 0 + a = a

... (0 + 1/2) = ... 1/2

<em>inverse property of multiplication</em> a/b · b/a = 1

37 · 2 · 1/2 = 37 · 2/1 · 1/2 = 37 · 1

<em>identity property of multiplication</em> a · 1 = 1 · a = a

37 · 1 = 37

6 0
3 years ago
Someone please help me
riadik2000 [5.3K]

Answer:

5.625

Step-by-step explanation:

So first do 112 / 360

Simplify it = 28 / 90 = 14 / 45

So 1.75 is 14 / 45 of the circumference.

The whole circumference is 1.75 * (45 / 14)

So the answer is 45 / 8 = 5.625

3 0
3 years ago
Find the LCM of 2 and 21
Alexus [3.1K]
The answer is 10 because it had
6 0
4 years ago
Item 7
Mariulka [41]

Answer:

A = 74.7^\circ

B = 42.5^\circ

C = 62.8^\circ

Step-by-step explanation:

Given

A = (-1,2) \to (x_1,y_1)

B = (2,8) \to (x_2,y_2)

C = (4,1) \to (x_3,y_3)

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2

For AB

A = (-1,2) \to (x_1,y_1)

B = (2,8) \to (x_2,y_2)

d = \sqrt{(-1 - 2)^2 + (2 - 8)^2

d = \sqrt{(-3)^2 + (-6)^2

d = \sqrt{45

So:

AB = \sqrt{45

For BC

B = (2,8) \to (x_2,y_2)

C = (4,1) \to (x_3,y_3)

BC = \sqrt{(2 - 4)^2 + (8 - 1)^2

BC = \sqrt{(-2)^2 + (7)^2

BC = \sqrt{53

For AC

A = (-1,2) \to (x_1,y_1)

C = (4,1) \to (x_3,y_3)

AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2

AC = \sqrt{(-5)^2 + (1)^2

AC = \sqrt{26

So, we have:

AB = \sqrt{45

BC = \sqrt{53

AC = \sqrt{26

By representation

AB \to c

BC \to a

AC \to b

So, we have:

a = \sqrt{53

b = \sqrt{26

c = \sqrt{45

By cosine laws, the angles are calculated using:

a^2 = b^2 + c^2 -2bc \cos A

b^2 = a^2 + c^2 -2ac \cos B

c^2 = a^2 + b^2 -2ab\ cos C

a^2 = b^2 + c^2 -2bc \cos A

(\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A

53 = 26 +45 - 2 * 34.21 * \cos A

53 = 26 +45 - 68.42 * \cos A

Collect like terms

53 - 26 -45 = - 68.42 * \cos A

-18 = - 68.42 * \cos A

Solve for \cos A

\cos A =\frac{-18}{-68.42}

\cos A =0.2631

Take arc cos of both sides

A =\cos^{-1}(0.2631)

A = 74.7^\circ

b^2 = a^2 + c^2 -2ac \cos B

(\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B

26 = 53 +45 -97.67 * \cos B

Collect like terms

26 - 53 -45= -97.67 * \cos B

-72= -97.67 * \cos B

Solve for \cos B

\cos B = \frac{-72}{-97.67}

\cos B = 0.7372

Take arc cos of both sides

B = \cos^{-1}(0.7372)

B = 42.5^\circ

For the third angle, we use:

A + B + C = 180 --- angles in a triangle

Make C the subject

C = 180 - A -B

C = 180 - 74.7 -42.5

C = 62.8^\circ

8 0
3 years ago
PLEASE HELP ASAP!!! WILL GIVE BRAINLIEST FOR BEST/RIGHT ANSWER!!!!!!!!
Nesterboy [21]
The answer is A, please mark brainliest.
7 0
3 years ago
Read 2 more answers
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