Answer:
3
Explanation:
Heterozygous mice at both loci would be BbAa genotype.
B (black) is dominant over b (white) but the presence of A results in agouti.
Crossing two heterozygous:
BbAa x BbAa
Progeny
<em>9 B_A_ - Agouti</em>
<em>3 bbA_ - agouti</em>
<em>3 B_aa - Black</em>
<em>1 bbaa - white</em>
Hence, 3 out of 16 progeny will be black in color.
<em>See the attached image for the Punnet's square analysis of the cross.</em>
