Answer:
Step-by-step explanation:
<u>Question 1</u>
<u>Part (a)</u> :
⇒ 6 × 6 × 6 × 6 × 6 × 6 × 6 = 6ˣ
⇒ 6⁷ = 6ˣ
⇒ x = 7
<u>Part (b)</u> :
⇒ y² = 169
⇒ √y² = √169
⇒ y = ± 13
⇒ y = 13, y = -13
<u>Question 2</u>
<u>Part (a)</u> :
⇒ (√5)² × (√3)²
⇒ 5 × 3
⇒ 15
<u>Part (b)</u> :
⇒ (∛9)³ × (√30)²
⇒ 9 × 30
⇒ 270
Answer:
D
Step-by-step explanation:
This is exponential growth, and to my understanding, the format goes:
<em>initial amount (percent growth/ decay)^time</em>
percent growth = (<em>decimal percent + 1)</em>
<em>percent decay = (1 - decimal percent) </em>
Your equation:
1500(1.02)^t
Using the above format, 1500 appears to be the initial amount, which increases by 2% per annum.
i think
This is equal to:
(8.9*4)(10^4*10^8)
pertinent rule: (a^b)(a^c)=a^(b+c)
(8.9*4)(10^12)
35.6X10^12
3.56X10^13 (and if we kept only significant figures....)
3.6X10^13
-2x+10^5 this should be I guess
