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Bezzdna [24]
2 years ago
9

Can someone please give me the answers (I’ll be giving brainliest)

Mathematics
1 answer:
Andre45 [30]2 years ago
8 0
I think it's the first three.
-7.5 < -7
-4 < -3
-0.5 < -1
(those are the inequalities after i put each of the values for x in the original equation)
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Solve the Equation <br> 2x-3=14<br> -x+3y=-6
andriy [413]

Step-by-step explanation:

If you lost "y" in the first equation.

\underline{+\left\{\begin{array}{ccc}2x-3y=14\\-x+3y=-6\end{array}\right}\qquad\text{add both sides of the equations}\\\\.\qquad x=8\\\\\text{Put the value of x to the first equation:}\\\\2(8)-3y=14\\16-3y=14\qquad\text{subtract 16 from both sides}\\-3y=-2\qquad\text{divide both sides by (-3)}\\y=\dfrac{2}{3}\\\boxed{x=8,\ y=\dfrac{2}{3}}

If first equation is correct.

2x-3=14\qquad\text{add 3 to both sides}\\2x=17\qquad\text{divide both sides by 2}\\x=8.5\\\\\text{Put the value of x to the second equation:}\\-8.5+3y=-6\qquad\text{add 8.5 to both sides}\\3y=2.5\qquad\text{divide both sides by 3}\\y=\dfrac{2.5}{3}\\y=\dfrac{25}{30}\\y=\dfrac{5}{6}\\\\\boxed{x=8.5,\ y=\dfrac{5}{6}}

6 0
2 years ago
Find the equation for the inverse of the relation <br> Y=2x+1
Naddik [55]
I thank the answer is 4

8 0
3 years ago
Shelley purchases several stuffed animals to give to charity. The price of each animal is listed in the chart. Which animal has
podryga [215]
The price of the duck because the 5 in the price of the horse is in the ones place. So you will have to divide by 10 to get to the 5 in the duck's price.
4 0
2 years ago
Compute the difference​ quotient, StartFraction f (x plus h )minus f (x )Over h EndFraction f(x+h)−f(x) h​, for the function f (
lawyer [7]

Answer:

The difference quotient for f(x)=3x^2 is 3 h + 6 x.

Step-by-step explanation:

The difference quotient is a formula that computes the slope of the secant line through two points on the graph of <em>f</em>. These are the points with x-coordinates x and x + h. The difference quotient is used in the definition the derivative and it is given by

\frac{f(x+h)-f(x)}{h}

So, for the function f(x)=3x^2 the difference quotient is:

To find f(x+h), plug x+h instead of x

f\left(x+h\right)=3 \left(h + x\right)^{2}

Finally,

\frac{f\left(x+h\right)-f\left(x\right)}{h}=\frac{\left(3 \left(h + x\right)^{2}\right)-\left(3 x^{2}\right)}{h}

\frac{3\left(\left(h+x\right)^2-x^2\right)}{h} \\\\\frac{3(h^2+2hx+x^2-x^2)}{h} \\\\\frac{3h\left(h+2x\right)}{h}\\\\3h+6x

The difference quotient for f(x)=3x^2 is 3 h + 6 x.

4 0
2 years ago
If 2(4x + 3)/(x - 3)(x + 7) = a/x - 3 + b/x + 7, find the values of a and b.
zmey [24]

Answer:

a=3 and b=5.

Step-by-step explanation:

So I believe the problem is this:

\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}

where we are asked to find values for a and b such that the equation holds for any x in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

\frac{2(4x+3)}{x-3}(x+7)}\cdot(x-3)(x+7)=\frac{a}{x-3}\cdot(x-3)(x+7)+\frac{b}{x+7}(x-3)(x+7)

2(4x+3)=a(x+7)+b(x-3)

As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

2(4\cdot -7+3)=a(-7+7)+b(-7-3)

2(-28+3)=a(0)+b(-10)

2(-25)=0-10b

-50=-10b

Divide both sides by -10:

\frac{-50}{-10}=b

5=b

Now we have:

2(4x+3)=a(x+7)+b(x-3) with b=5

I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.

2(4\cdot 3+3)=a(3+7)+b(3-3)

2(12+3)=a(10)+b(0)

2(15)=10a+0

30=10a

Divide both sides by 10:

\frac{30}{10}=a

3=a

So a=3 and b=5.

4 0
2 years ago
Read 2 more answers
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