Answer: see below
<u>Step-by-step explanation:</u>
1) 10, 2, 1.2, 1.12, 1.112, 1.1112
t₁ = 10
t₂ = 10/10 + 1 = 2
t₃ = 2/10 + 1 = 1.2
t₄ = 1.2/10 + 1 = 1.12
t₅ = 1.12/10 + 1 = 1.112
t₆ = 1.112/10 + 1 = 1.1112
2) 10, 2, -2, -4, -5, -5.5, ...
t₁ = 10
t₂ = 10/2 - 3 = 2
t₃ = 2/2 - 3 = -2
t₄ = -2/2 - 3 = -4
t₅ = -4/2 - 3 = -5
t₆ = -5/2 - 3 = -5.5
Using the normal distribution, it is found that 0.26% of the items will either weigh less than 87 grams or more than 93 grams.
In a <em>normal distribution</em> with mean and standard deviation
, the z-score of a measure X is given by:
In this problem:
We want to find the probability of an item <u>differing more than 3 grams from the mean</u>, hence:
The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.
2 x 0.0013 = 0.0026
0.0026 x 100% = 0.26%
0.26% of the items will either weigh less than 87 grams or more than 93 grams.
For more on the normal distribution, you can check brainly.com/question/24663213