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KATRIN_1 [288]
2 years ago
8

Using the data provided below, calculate the corrected wavelength for a spectroscope reading of 6.32.

Physics
1 answer:
weqwewe [10]2 years ago
6 0

Answer:

646.6 nm

Explanation:

Using the data given, we fit a linear model :

Spectroscope Readings Known Helium Wavelengths (nm)

3.65 388.9

4.75 486.6

4.90 501.6

5.65 587.6

6.45 667.8

7.00 706.5

Using technology like excel to fit the model, the regression model obtained is :

Y = 97.96582X + 27.48458

Where, y is the predicted or corrected wavelength value.

This mod could be used to calculate the corrected wavelength for a given Spectroscope value :

Given a Spectroscope value of 6.32 ; the corrected wavelength is obtained by replacing x in the equation by 6.32 and calculate y ;

Y = 97.96582X + 27.48458

x = 6.32

Y = 97.96582(6.32) + 27.48458

Y = 619.1439824 + 27.48458

Y = 646.6285624

Corrected wavelength value is : 646.6

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Actual displacement that he required to move

d_1 = 5.4 km towards North

Displacement that he moved due to snow is

d_2 = 8.1 km at 47 degree North of East

now in vector component form we can say

d_1 = 5.4 \hat j

d_2 = 8.1 cos47 \hat i + 8.1 sin47 \hat j

d_2 = 5.52 \hat i + 5.92 \hat j

now the displacement that is more required to reach the destination is given as

d = d_1 - d_2

d = 5.4\hat j - (5.52 \hat i + 5.92\hat j)

d = -5.52 \hat i - 0.52 \hat j

so the magnitude of the displacement is given as

d = \sqrt{5.52^2 + 0.52^2}

d = 5.54 km

its direction is given as

\theta = tan^{-1}\frac{0.52}{5.52} = 5.38 degree

so it is 5.54 km towards 5.38 degree North of West.

4 0
3 years ago
One particle has a charge of 2.15 x 10^ -9 while another particle has a charge of 3.22 x 10^ -9 If the two particles are separat
marin [14]

Answer:

B. 2.77 x 10^{-4} N

Explanation:

The required force can be calculated by:

F = \frac{Kq_{1}q_{2}  }{d^{2} }

Where F is the force between the particles, K is the coulomb's constant (9 x 10^{9} Nm^{2}/C^{2}), q_{1} is the charge on the first particle, q_{2} is the charge on the second particle and d^{2} is the distance between the particles.

So that:

F = \frac{9*10^{9}*2.15*10^{-9} *3.22*10^{-9}  }{(0.015)^{2} }

  = \frac{6.2307*10^{-8} }{(2.25*10^{-4} }

  = 2.7692 x 10^{-4}

 The force between the particles is 2.77 x 10^{-4} N.

3 0
2 years ago
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3 years ago
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A 222 kg bumper car moving right at 3.10 m/s collides with a 165 kg bumper car moving 1.88 m/s left Find the total momentum of t
Svetlanka [38]

Answer:

Total momentum of the system is 378 kg-m/s

Explanation:

It is given that,

Mass of first bumper car, m₁ = 222 kg

Velocity of first bumper car, v₁ = 3.10 m/s (in right)

Mass of other bumper car, m₂ = 165 kg

Velocity of second bumper car, v₂ = -1.88 m/s (in left)

Momentum of the system is given by the product of its mass and velocity. So, the total momentum of this system is given by :

p=m_1v_1+m_2v_2

p=222\ kg\times 3.10\ m/s+165\ kg\times (-1.88\ m/s)

p = 378 kg-m/s

Hence, the total momentum of the system is 378 kg-m/s

5 0
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On a far-away (hypothetical) planet, a student is conducting an experiment to study vertical motion. The student fires a cannon
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Yeah it’s pretty much positive
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2 years ago
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