Below, the two-way table is given for a class of students. Freshmen Sophomore Juniors Seniors Total Male 4 6 2 2 Female 3 4 6 3
Total If a student is selected at random, find the probability the student is a female given that it's a junior. P( Female | Junior ) = [?] % Round to the nearest whole percent.
1 answer:
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Complete Question:
Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric force on sphere B due to sphere A is F . F. The magnitude of the electric force on sphere A due to sphere B must be:
A. 2F
B. F/4
C. F/2
D. F
E. 4F
Answer:
D.
Explanation:
If both spheres can be treated as point charges, they must obey the Coulomb's law, that can be written as follows (in magnitude):
As it can be seen, this force is proportional to the product of the charges, so it must be the same for both charges.
As this force obeys also the Newton's 3rd Law, we conclude that the magnitude of the electric force on sphere A due to sphere B, must be equal to the the magnitude of the force on the sphere B due to the sphere A, i.e., just F.
Answer:
292.3254055 W/m²
469.26267 V/m
Explanation:
P = Power of bulb = 90 W
d = Diameter of bulb = 7 cm
r = Radius =
= Permittivity of free space =
c = Speed of light =
The intensity is given by
5% of this energy goes to the visible light so the intensity is
The visible light intensity at the surface of the bulb is 292.3254055 W/m²
Energy density of the wave is
Energy density is also given by
The amplitude of the electric field at this surface is 469.26267 V/m
Amplitude of a magnetic field is given by
The amplitude of the magnetic field at this surface is