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kolbaska11 [484]
3 years ago
12

In an earthquake, a P wave is a longitudinal wave. It moves through soil and rock as a

Physics
2 answers:
ElenaW [278]3 years ago
7 0
<span>In an earthquake, a P wave is a longitudinal wave. It moves through soil and rock as a C. series of compressions and rarefactions.</span>
Andru [333]3 years ago
7 0

Answer:   C. series of compression and rarefaction.

Explanation:

A longitudinal wave is the one where medium particles oscillate in the direction of wave motion. The energy is transferred by series of compression and rarefaction. Compression is region of high density of medium particles and rarefaction is the low density region through which the wave travels.

<u>Thus, a P wave of earthquake which is a longitudinal wave traverses through soil by a series of compression and rarefaction. </u>

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Electrons are added into the outermost what in groups 1 &amp; 2
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S orbital.

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What happens if magnesium is added to hydrochloric acid (hci) in a single replacement reaction
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It produces hydrogen gas
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3 years ago
To practice Problem-Solving Strategy 17.1 for wave interference problems. Two loudspeakers are placed side by side a distance d
Nimfa-mama [501]

Complete Question

The compete question is shown on the first uploaded question

Answer:

The speed is  v  =  350 \  m/s  

Explanation:

From the question we are told that

   The  distance of separation is  d =  4.00 m  

  The distance of the listener to the center between the speakers is  I =  5.00 m

  The change in the distance of the speaker is by k  =  60 cm  =  0.6 \  m

    The frequency of both speakers is f =  700 \  Hz

Generally the distance of the listener to the first speaker is mathematically represented as

       L_1  =  \sqrt{l^2 + [\frac{d}{2} ]^2}

       L_1  =  \sqrt{5^2 + [\frac{4}{2} ]^2}

        L_1  =   5.39 \  m

Generally the distance of the listener to second speaker at its new position is  

          L_2  =  \sqrt{l^2 + [\frac{d}{2} ]^2 + k}

       L_2  =  \sqrt{5^2 + [\frac{4}{2} ]^2 + 0.6}

        L_2  =   5.64  \  m  

Generally the path difference between the speakers is mathematically represented as

        pD  = L_2 - L_1  =  \frac{n  *  \lambda}{2}

Here \lambda is the wavelength which is mathematically represented as

         \lambda =  \frac{v}{f}

=>    L_2 - L_1  =  \frac{n  *  \frac{v}{f}}{2}

=>    L_2 - L_1  =  \frac{n  *  v}{2f}  

=>    L_2 - L_1  =  \frac{n  *  v}{2f}  

Here n is the order of the maxima with  value of  n =  1  this because we are considering two adjacent waves

=>    5.64 - 5.39   =  \frac{1  *  v}{2*700}      

=>    v  =  350 \  m/s  

7 0
3 years ago
A stretched string is 2.11 m long and has a mass of 19.5 g. When the string is oscillated at 440 Hz, which is the frequency of t
Katarina [22]

Answer:

efsfefsfsdf

Explanation:

efsfesef

7 0
3 years ago
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