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Vilka [71]
3 years ago
8

Why might a telescope be built high in the mountains above weather sys

Physics
2 answers:
Debora [2.8K]3 years ago
6 0

Large telescopes aren't built on mountain tops for the purpose of watching
weather systems.  The ones that are built at high altitudes are intended to be
used to observe celestial objects ... planets, stars, galaxies, comets, nebulae,
quasars, novae, and the space around black holes. 

The way a telescope does that is:  It collects visible light and radiation with
other electromagnetic wavelengths, and people then analyze the radiation
that the telescope has collected.

When we use the telescope to do that, we want anything it collects to be
as close as possible to the radiation that actually left the star.  The problem
is that anything the telescope collects must come down through AIR. The trip
through air changes the radiation before you have a chance to collect it, so
you can never see exactly what left the star.

The solution: 

==> Build your telescope in a place where the light goes through less air
before it reaches the telescope. 

==> Or ... if you can work it out somehow ... through NO air.

That means: 

==> Build your telescope at high altitude, on a mountaintop, where
most of the Earth's air is BELOW you.

==> Or put your telescope in a spacecraft.  Put the spacecraft in orbit
around the Earth, where there is almost NO air, and let the telescope
send its pictures and other data to you by radio. 

Schach [20]3 years ago
6 0

you could look down on the weather systems AND look up into the troposphere to see every weather system or whatever is happening in the troposphere
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The natural satelite Europa and the planet Mars are the two rock systems more likely to earth on their conditions all about solar system. Europa has a huge liquid water ocean and temperature is pretty similar to earth, Mars also has water but it's in solid state and the temperature also is good, not during the nights but still is good enough.

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The table below shows the average wind speeds of four hurricanes in Florida. Florida Hurricanes Hurricane | Average Wind Speed (
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As part of an interview for a summer job with the Coast Guard, you are asked to help determine the search area for two sunken sh
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Answer:

The resultant velocity is  v_t=10 knots

Explanation:

Apply the law of conservation of momentum

     M_L *v_L + M_f * V_f = (M_L + M_f) v_t

Where M_L is the mass of the Luxury Liner = 40,000 ton

            v_L is the velocity of Luxury Liner = 20 knots due west

            M_f mass of freighter = 60,000

           v_f is the velocity of freighter = 10 knots due north

Apply the law of conservation of momentum toward the the west direction

         v_f = 0 \ knots

So the equation would be

              M_L *v_L = (M_L + M_f) v_t

Substituting values

            40000*20 = (40000+ 60000)v_t_w

Where v_t_w the final velocity due west

Making v_t_w the subject

          v_t_w = \frac{40,000* 20}{(40000 + 60000)}

                = 8 \ knots

Apply the law of conservation of momentum toward the the north direction          

          v_L = 0 \ knots

So the equation would be

           M_f *v_f = (M_L + M_f) v_t_n

Where v_t_n the final velocity due north

     Making v_t_n the subject

          v_t_n = \frac{60,000* 10}{(40000 + 60000)}

                = 6 \ knots

The resultant velocity is

       v_t = \sqrt{v_t_w^2 + v_t_n^2}

            = \sqrt{8^2 +6^2}

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3 years ago
Sarah, whose mass is 40 kg, is on her way to school after a winter storm when she accidentally slips on a patch of ice whose coe
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Sarah's acceleration is -0.49 m/s^2

Explanation:

The force of kinetic friction acting on Sarah has a magnitude which is given by:

F_f = \mu mg

where

\mu is the coefficient of kinetic friction

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Moreover, according to Newton's second law of motion, we know that the net force on Sarah is equal to its mass times its acceleration:

F=ma

where a is the acceleration

Since the force of friction is the only force acting on Sarah, we can say that the net force is equal to the force of friction, therefore:

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a=-\mu g

And substituting the following values:

\mu = 0.05 (coefficient of friction)

g=9.81 m/s^2 (acceleration of gravity)

we find:

a=-(0.05)(9.81)=-0.49 m/s^2

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