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Minchanka [31]
3 years ago
12

Which type of function best models the given data?

Mathematics
2 answers:
kherson [118]3 years ago
5 0

Answer:

3)

Step-by-step explanation:

Draw the graph and youll see

mrs_skeptik [129]3 years ago
4 0

Answer:

Exponential growth function

Step-by-step explanation:

It multiplies by 3 each time

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En la finca de los padres de un amigo han sacado un total de 18.367,42 kg de aceitunas. Ellos tienen 648 olivos. ¿Cuántos kg de
ElenaW [278]

Answer:

Promedio de kg por arbol= 28.35kg

Step-by-step explanation:

Dada la siguiente información:

Cantidad de árboles= 648

Cantidad total de kg= 18.367,42 kg

<u>Para calcular el promedio de kg por arbol, tenemos que usar la siguiente formula:</u>

<u></u>

Promedio de kg por arbol= cantidad total de kg / número de arboles

Promedio de kg por arbol= 18.367,42 / 648

Promedio de kg por arbol= 28.35kg

3 0
3 years ago
X divided by -7 is less than or equal too 8
mestny [16]
X/-7 ≤ 8 ⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀
5 0
3 years ago
50 points !!! <br> Will also mark brainliest <br> Show work for brainliest
Arlecino [84]

Answer:

a2-3a-7=0

Step-by-step explanation:

hope this helps

3 0
2 years ago
Read 2 more answers
If you were asked to convert 75 m/s to km/hr, which conversation factors would you need to use. Select all that apply.
Vilka [71]

Answer:

You need to use A, B, and C.

Step-by-step explanation:

Let's treat the units as variables. I'll illustrate why in a moment.

75 m/s =\frac{75m}{1s} \\\\\frac{75m}{1s}*\frac{1km}{1000m}=\frac{75m*km}{1000m*s}\\\\\frac{75m*km}{1000m*s}*\frac{60s}{1min}=\frac{(75*60)m*km*s}{1000m*s*min}\\\\\frac{4500m*km*s}{1000m*s*min}*\frac{60min}{1h}=\frac{4500m*km*s*min}{1000m*s*min*h}

Now, as you can see, we have a giant mess of units to deal with. This is where we can treat the units like separate variables and use a bit of algebra to make our lives easier:

\frac{4500m*km*s*min}{1000m*s*min*h}=\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}\\\\\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}=\frac{4500}{1000}*\frac{m}{m}*\frac{km}{1}*\frac{s}{s}*\frac{min}{min}*\frac{1}{h}\\\\\frac{4500}{1000}*\frac{m}{m}*\frac{km}{1}*\frac{s}{s}*\frac{min}{min}*\frac{1}{h}=\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}=\frac{4500}{1000}*1*\frac{km}{1}*1*1*\frac{1}{h}\\\\\frac{4500}{1000}*1*\frac{km}{1}*1*1*\frac{1}{h}=\frac{4500}{1000}*\frac{km}{h}\\

\frac{4500}{1000}*\frac{km}{h}=\frac{45}{1}*\frac{km}{h}=45 \frac{km}{h}

So, backtracking through that entire mess, we had to use \frac{1km}{1000m} ,\frac{60s}{1min} ,\frac{60min}{1h}.

These correspond to the options of A, C, and B accordingly.

So you need to use A, B, and C.

8 0
3 years ago
Write the expression in simplest form.<br> ( 4 = + 3) – 2(- \ - - })= 0
Dimas [21]

Answer:

3^x=9^{x+5}

Step-by-step explanation:

3^x=9^{x+5}

x^2-x-6=0

x^4-5x^2+4=0

\sqrt{x-1}-x=-7

\left|3x+1\right|=4

\log _2\left(x+1\right)=\log _3\left(27\right)

3^x=9^{x+5}

If request to solve;

\mathrm{Convert\:}9^{x+5}\mathrm{\:to\:base\:}3

9^{x+5}=\left(3^2\right)^{x+5}

\mathrm{Solve\:}\:x=2\left(x+5\right):\quad x=-10

6 0
3 years ago
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