As e is point between df. So we can write df as
df = de + ef
As given df = 78 , de = 5x - 9 , ef = 2x + 10.
So we can write
78 = 5x - 9 + 2x + 10
78 = 7x + 1
On subtracting 1 on booth side
78 - 1 = 7x +1 - 1
77 = 7x
On dividing both side by 7.

11 = x
So x = 11.
So ef = 2x + 10 = 2*11 + 10 = 22 + 10 = 32
Given h(x)=5x-3 and j(x)=-2x.
So, j(2) = -2*2 = -4
So, h[j(2)] = h(-4)= (5*-4) -3 = -20-3 = -23
Hence option D is correct.
Answer:
3053.63 Is the answer
Step-by-step explanation:
V=4/3*3.14*9*9*9
Values is 6 for lmso is a parellelle gram