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dimulka [17.4K]
3 years ago
15

HEEEEEEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLP please

Mathematics
1 answer:
djverab [1.8K]3 years ago
5 0

Answer:

B

Step-by-step explanation:

The y-intercept is 2 and the slope is 1. Therefore, the answer is 2y=x. :)

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Give the ordered pair of the 3rd Critical point.<br> Y = 4cos10(x - 12°) +16
lord [1]
So it would be x12 to the 2nd power, kinda hard to explain but i really hope this helped
6 0
3 years ago
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What is the measure of the other acute angle ?
Vaselesa [24]

Answer:

62^{o}

Step-by-step explanation:

All the angles in a triangle add up to 180^{o}

Every right angle triangle has a right angle in it which is 90^{o}

So to find the remaining angle, you do 180^{o} - 90^{o} - 28^{o} = 62^{o}

7 0
2 years ago
Help, I don't remember​
GenaCL600 [577]

Answer:

  x = 144

Step-by-step explanation:

What you need to remember about this geometry is that all of the triangles are similar. As with any similar triangles, that means ratios of corresponding sides are proportional. Here, we can write the ratios of the long leg to the short leg and set them equal to find x.

  x/60 = 60/25

Multiply by 60 to find x:

  x = (60·60)/25

  x = 144

_____

<em>Comment on this geometry</em>

You may have noticed that the above equation can be written in the form ...

  60 = √(25x)

That is, the altitude from the hypotenuse (60) is equal to the geometric mean of the lengths into which it divides the hypotenuse (25 and x).

This same sort of "geometric mean" relation holds for other parts of this geometry, as well. The short leg of the largest triangle (the hypotenuse of the one with legs 25 and 60) is the geometric mean of the short hypotenuse segment (25) and the total hypotenuse (25+x).

And, the long leg of the large triangle (the hypotenuse of the one with legs 60 and x) is the geometric mean of the long hypotenuse segment (x) and the total hypotenuse (25+x).

While it can be a shortcut in some problems to remember these geometric mean relationships, you can always come up with what you need by simply remembering that the triangles are all similar.

3 0
3 years ago
The work W required to move a particle from a far distance to within radius r of another particle varies jointly as the product
tangare [24]

Answer:

W = kq1q2 / r

Step-by-step explanation:

W varies jointly as the product of q1 and q2 and inversely as radius r

Product of q1 and q2 = q1q2

W = (k*q1"q2) / r

W = kq1q2 / r

Where,

W = work

q1 = particle 1

q2 = particle 2

r = radius

k = constant of proportionality

The answer is W = kq1q2 / r

5 0
3 years ago
Find the angles, θ&lt;0&lt;360, that satisfy the equation below, to the nearest 10th of a degree.
Irina-Kira [14]

Step-by-step explanation:

\tan( \theta)  =  \frac{8}{7}  \\  \theta =  \tan {}^{ - 1} (  \frac{8}{7} ) \\  \theta = 48.8 \degree,228.8

7 0
2 years ago
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