Let n be the sum of all 6 numbers:
In the 1st case n/6 = 41 ==> n =246
in the 2nd case n'/5 = 46===> n' =230, the unknown number is n-n' =246-230
= 16
If you say its easy, then why don't you figure out yourself? Or ask the teacher?
How to solve your problem
9−4+3
9x−4+3x9x-4+3x9x−4+3x
Simplify
1
Combine like terms
9−4+3
9x−4+3x{\color{#c92786}{9x}}-4+{\color{#c92786}{3x}}9x−4+3x
12−4
12x−4{\color{#c92786}{12x}}-412x−4
Solution
12−4
SO D
-5x-12>6x-4
To Solve the inequality we need to get x alone
-5x-12>6x-4
first we remove -12, for that we add 12 on both sides
-5x-12+12>6x-4+12
-5x > 6x +8
Now subtract 6x from both sides
-5x -6x> 6x-6x +8
-11x > 8
Divide by -11. when we divide by -11 we flip the inequality . so > becomes <

We need to give the answer in interval notation.
x is less than -8/11 so x value starts from -8/1 and goes to -infinity(left)
So interval notation is (-∞,
)
Number 3 i would say i think it is