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vova2212 [387]
3 years ago
12

1 1/5 is 6% of what number?

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
7 0

Answer:

36.67

Step-by-step explanation:

11/5=2.2

let the unknown no be x

6% of x=2.2

6/100 * x = 2.2

6x = 2.2*100

x = 220/6

x= 36.67

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A 6-foot tall man is standing in front of a school and notices his shadow measures 10 feet. At the same time, he notices the fla
irga5000 [103]

Answer:

The tall of the flag pole is 51 ft answer (A)

Step-by-step explanation:

∵ The tall of the man = 6 ft

∵ The his shadow = 10 ft

∵ The shadow of the flag pole = 85 ft

∵ Tall of the man/tall of the flag = shadow of the man/shadow

   of the flag

∴ 6/x = 10/85 ⇒ where x is the tall of the flag

∴ x = (6 × 85) ÷ 10 = 510 ÷ 10 = 51 ft

∴ The tall of the flag pole is 51 ft

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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8 0
2 years ago
Point F is located on the coordinate grid at (-8.35, -2.14). In which quadrant is Point F located?
belka [17]

Answer:

simple. quadrant III

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4 0
2 years ago
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Can we obtain a diagonal matrix by multiplying two non-diagonal matrices? give an example
polet [3.4K]
Yes, we can obtain a diagonal matrix by multiplying two non diagonal matrix.

Consider the matrix multiplication below

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]   \left[\begin{array}{cc}e&f\\g&h\end{array}\right] =  \left[\begin{array}{cc}a e+b g&a f+b h\\c e+d g&c f+d h\end{array}\right]

For the product to be a diagonal matrix,

a f + b h = 0 ⇒ a f = -b h
and c e + d g = 0 ⇒ c e = -d g

Consider the following sets of values

a=1, \ \ b=2, \ \ c=3, \ \ d = 4, \ \ e=\frac{1}{3}, \ \ f=-1, \ \ g=-\frac{1}{4}, \ \ h=\frac{1}{2}

The the matrix product becomes:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}\frac{1}{3}&-1\\-\frac{1}{4}&\frac{1}{2}\end{array}\right] = \left[\begin{array}{cc}\frac{1}{3}-\frac{1}{2}&-1+1\\1-1&-3+2\end{array}\right]= \left[\begin{array}{cc}-\frac{1}{6}&0\\0&-1\end{array}\right]

Thus, as can be seen we can obtain a diagonal matrix that is a product of non diagonal matrices.
8 0
3 years ago
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The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.0 minutes and
strojnjashka [21]

Answer:

P ( 5 < X < 10 ) = 1

Step-by-step explanation:

Given:-

- Sample size n = 49

- The sample mean u = 8.0 mins

- The sample standard deviation s = 1.3 mins

Find:-

Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.

Solution:-

- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:

                                   X ~ N ( u , s /√n )

Where

                            s /√n = 1.3 / √49 = 0.2143

- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:

                        P ( 5 < X < 10 ) = P (    (5 - 8) / 0.2143 <  Z  <  (10-8) / 0.2143   )

                                                 = P ( -14.93 < Z < 8.4 )

- Using standard Z-table we have:

                        P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1        

7 0
3 years ago
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