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KiRa [710]
3 years ago
15

I dropped my sandwich the pool once

Mathematics
1 answer:
kykrilka [37]3 years ago
5 0

Answer:

cool i dropped my little brother in the pool once

Step-by-step explanation:

i sliped and dropped him

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I need this nowwww plss
Zielflug [23.3K]

I think the answer is 1/23

Please tell me if I'm wrong.

3 0
3 years ago
A plant produces sport drinks, which must be within 0.15 fluid ounces of the advertised 10 fluid ounces on the label. If x repre
Sphinxa [80]

Answer:

|x − 10| = 0.15; x = 9.85 ounces

Step-by-step explanation:

its common math skills but yea.

4 0
2 years ago
Im sorry for so many questions but i need help badly.
vlada-n [284]
The ratio of the circumference to the diameter is defined as pi
pi=circumference/diameter
that is how they got pi
in this question it woul be 15.7/5 which would be 3.14,





c=2pir
a=pir^2

c=2pir=16pi
divide both sides by 2pi
r=8

a=pir^2
a=pi8^2
a=pi64
a=64pi in²
5 0
3 years ago
CAN SOMEONE PLEASE HELP ME PLEASE help
strojnjashka [21]

Answer:

I got uuuuu

Step-by-step explanation:

Here you go

11x-2=75 right and its an corresponding sooooo they equal each other so the other one is 75 also  if u want a my math lmk

3 0
3 years ago
Let A(t) be the area of a circle with radius r(t), at time t in min. Suppose the radius is changing at the rate of drdt=6 ft/min
mylen [45]

Answer:

The rate of change is 108\pi ft^(2)/min

Step-by-step explanation:

The area of a circle is given by the following equation:

A(t) = \pi r^{2}

To solve this question, we have to realize the implicit differentiation in function of t. We have two variables, A and r. So

\frac{dA(t)}{dt} = 2\pi r \frac{dr}{dt}

We have that:

\frac{dr}{dt} = 6, r = 9.

We want to find \frac{dA}{dt}

So

\frac{dA(t)}{dt} = 2\pi*9*6

\frac{dA}{dt} = 108\pi

Since the area is in square feet, the rate of change is in ft^(2)/min.

So the rate of change is 108\pi ft^(2)/min

5 0
3 years ago
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