Answer: 28
Step-by-step explanation: All you have to do is multiply 70 by 4 and take away the zero to get your answer
Answer:
the question is incomplete, so I looked for a similar one:
<em>After the release of radioactive material into the atmosphere from a nuclear power plant, the hay was contaminated by iodine 131 ( half-life, 8 days). If it is all right to feed the hay to cows when 10% of the iodine 131 remains, how long did the farmers need to wait to use this hay? </em>
iodine's half life (we are given x, we need to find b):
0.5A₀ = A₀eᵇˣ
x = 8 days
we eliminate A₀ from both sides
0.5 = eᵇ⁸
ln 0.5 = ln eᵇ⁸
-0.69315 = b8
b = -0.69315 / 8 = -0.08664
since the farmers need to wait until only 10% of the iodine remains (we already calculated b, now we need to find x):
0.1A₀ = A₀eᵇˣ
0.1 = eᵇˣ
ln 0.1 = bx
where b = -0.08664
x = ln 0.1 / -0.08664 = -2.302585 / -0.08664 = 26.58 days
Answer:
-4(8-3x)>or =6x-8
Step-by-step explanation:
open d bracket
-32+12x >or = 6x-8
collect like terms
12x-6x >or =-8+32
6x = 24
divide both sides by 6
x= 4
672 dollars is the net price because 15 percent off of 10 percent of 662 dollars is about 10 dollars and 10 + 662 is 672
4x^4
so the answer would be
4x^4(18x-20)
