I would do this by first listing the multiples of 6 until I start to see a pattern with the one's digit.
6x0=0
6x1=6
6x2=12
6x3=18
6x4=24
6x5=30
6x6=36
6x7=42
6x8=48
...
The digits in bold are the one's digits so those are the only ones we really care about. If you list just them it looks like: 0,6,2,8,4,0,6,2,8
Notice how the first set of 5 numbers seems as though it repeats in the 6th, 7th, and 8th numbers. This probably means the pattern continues infinitely so the first 5 numbers are all the one's digits that can come from multiples of 6. Thus your answer is: 0,6,2,8,or 4
You have to plug in the numbers for x
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Answer:
Step-by-step explanation:
Ir order to find the value of n in the given linear equation: 
you have to perform the properties of equalities to obtain an equivalent equation.
You have to perform these properties in each side of the equation.
Applying the subtraction property (which is the subtraction of the same number to each side of the equation):
Adding 
to each side:
This way you can obtain the value of n
Solving the subtraction of the fractions and simplifying:
Answer:
q=13
Step-by-step explanation:
Solve : -q+13 = 0
Subtract 13 from both sides of the equation :
-q = -13
Multiply both sides of the equation by (-1) : q = 13
