When y=2 and y=5
1. 2y-1 and (3y-5+y or 4y-5)
when y=2 ; 2(2)-1 = 3 and 4(2)-5=3
when y=5 ; 2(5)-1 = 9 and 4(5)-5=15
----nonequivalent-----
2.5y+4 and (7y+4-2y or 5y+4)
so you don't have to place any value in because 5y+4 and 7y+4-2y are equal,
whatever you place any value in, it will be all the same then
-----equivalent------
and no need to find more
1/7 is your answer. It can't be reduced any further. If there is supposed to be a problem, next time, add it.
Answer:
rule add 15 subtract 10
Step-by-step explanation:
rule add 15 subtract 10
If you’re talking about answers a would be the option first b would be 2nd and c would be 3rd
C. Vertex (x,y). The vertex is right in the middle of the quadratic graph.
