Answer:
we know that
the relationship between the 2-dimensional polar and Cartesian coordinates is
r = √(x² + y²)
Θ = tan⁻¹ (y/x)
so
Part a) (2, −2)---------> this point belong to the IV quadrant
r = √(x² + y²)------ r = √(2² + (-2)²)-----> r=√8
Θ = tan⁻¹ (y/x)---- Θ = tan⁻¹ (2/2)----> 45°
remember that the point belong to the IV quadrant
so
Θ=360-45-----> Θ=315°
the answer part A) is
(r,Θ)=(√8,315°)
Part b) (-1, 3)---------> this point belong to the II quadrant
r = √(x² + y²)------ r = √(-1² + (3)²)-----> r=√10
Θ = tan⁻¹ (y/x)---- Θ = tan⁻¹ (3/1)----> 71.57°
remember that the point belong to the II quadrant
so
Θ=180-71.57-----> Θ=108.43°
the answer part B) is
(r,Θ)=(√10,108.43°)
mark me branlest plz hope it helps
Answer:
x^2+2x
Step-by-step explanation: You would take x and multiply it by x and get X^2 then you would take x anm multiply it by 2 to get 2x. It is distributing
