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sergeinik [125]
3 years ago
9

Which of the following functions of the digestive tract and accessory organs involves the progressive dehydration of indigestibl

e materials and organic wastes prior to elimination from the body?
A. Ingestion
B. Mastication
C. Compaction
D. Defaction
Biology
1 answer:
emmainna [20.7K]3 years ago
6 0

Answer:

C. Compaction

Explanation:

Chyme enters from the small intestine into the large intestine. In the large intestine, chyme becomes solid or semisolid as the water is absorbed from it. Absorption of excess water from chyme to convert it into the feces in the large intestine is called compaction. Feces consist of water, inorganic salts, unabsorbed digested materials, and indigestible parts of food.  During compaction, enough water is absorbed and this makes large intestine one of the important organs in maintaining the body’s water balance.

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The strong affection that we have for those with whom our lives are deeply involved, such as our parents or close friends is cal
IgorLugansk [536]

Answer:

Companionate love

Explanation:

we know that when we have strong affection with we live is deeply involved that is Companionate love because Companionate love is about trust and commitment and intimacy and the affection  

so that when we go for long term relationship compassionate love  feel passionate about each other  

so here we can say correct option is c. Companionate love

3 0
3 years ago
At each step of the food chain, how much energy is used by the organism and how much is stored in their tissues?
Katyanochek1 [597]
90% of the energy is used up between levels, and the remaining 10% stays in the tissues to be passed on.
6 0
2 years ago
In plants, ______________ are defined as haploid (1n) cells that develop into gametophytes. Gametophytes, in turn, produce eithe
soldi70 [24.7K]

Answer: SPORES are defined as haploid (1n) cells which develops into gametophytes.

Gametophytes inturn produce either haploid (1n) male or females GAMETES that can fuse to form diploid ZYGOTES.

This basically explains what goes on in Meiosis.

8 0
3 years ago
Each cell in an individual's body carries certain molecules that tell the body they belong to that individual. those molecules a
Maksim231197 [3]

Answer:

MHC Markers

Explanation:

The function of MHC molecules is to display peptide fragments derived from pathogens on the cell surface for recognition by the appropriate T cells.

8 0
1 year ago
A fish maintains its depth in fresh water by adjusting the air content of porous bone or air sacs to make its average density th
Volgvan

Answer:

0.153

Explanation:

We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.

So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.

ρVg = ρ'V'g + ρ"V"g

ρV = ρ'V'g + ρ"V"

Its new body volume = volume of water displaced, V = V' + V"

ρ(V' + V") = ρ'V' + ρ"V"

ρV' + ρV" = ρ'V' + ρ"V"

ρV' - ρ"V'  = ρ'V" - ρV"

(ρ - ρ")V'  = (ρ' - ρ)V"

V'/V" = (ρ - ρ")/(ρ' - ρ)

= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)

= (0.9988 g/cm³ ÷ 0.18 g/cm³)

V'/V" = 5.55

Since V = V' + V"

V' = V - V"

(V - V")/V" = 5.55

V/V" - V"/V" = 5.55

V/V" - 1 = 5.55

V/V" = 5.55 + 1

V/V" = 6.55

V"/V = 1/6.55

V"/V = 0.153

So, the fish must inflate its air sacs to 0.153 of its expanded body volume

5 0
3 years ago
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