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Jet001 [13]
3 years ago
9

Find the volume of the triangular prism ​

Mathematics
1 answer:
RoseWind [281]3 years ago
7 0

Answer:

<h3>168cm3</h3>

Step-by-step explanation:

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Need help please thanks
frozen [14]

Answer:

x-intercept = 3 ; y-intercept = -5

Step-by-step explanation:

Lets rearrange the equation into the form y = mx + b:

5x - 3y = 15

-3y = 15 - 5x

Divide by -3:

y = 5x/3 - 5

Here we know that b (-5) is the y-intercept, and we can find the x-intercept by starting at the y-intercept and using the slope till we get the x-intercept. Or you can set y = 0 and solve for x, either way you get x-intercept = 3.

5 0
2 years ago
Read 2 more answers
Please help ASAP. Trigonometry
Contact [7]

Answer:

  cos(52°) = 18/x

  x = 18·sec(52°)

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that ...

  Cos = Adjacent/Hypotenuse

In this geometry, that means ...

  cos(52°) = 18/x

You can use the relation sec(x) = 1/cos(x) to rewrite this as ...

  x = 18·sec(52°)

_____

You can also use the complementary angle and the complementary trig function.

  sin(90° -52°) = 18/x

4 0
2 years ago
Write the equation of the line in fully simplified slope-intercept form.
PtichkaEL [24]

Answer:

Consider points (0, -5) and (-6, -1)

» General equation of a line:

{ \tt{y = mx + c}}

  • m is slope
  • c is y-intercept

<u> </u><u>S</u><u>l</u><u>o</u><u>p</u><u>e</u><u> </u><u>(</u><u>m</u><u>)</u><u>:</u>

{ \tt{m =  \frac{ - 1 - ( - 5)}{ - 6 - 0} }} \\  \\ { \tt{m =  \frac{4}{ - 6} }} \\  \\ { \tt{m =  -  \frac{2}{3} }}

<u> </u><u>y</u><u>-</u><u>i</u><u>n</u><u>t</u><u>e</u><u>r</u><u>c</u><u>e</u><u>p</u><u>t</u><u> </u><u>(</u><u>c</u><u>)</u><u>:</u>

{ \tt{y = mx + c}}

consider point (0, -5)

{ \tt{ - 5 = c}} \\ { \tt{c =  - 5}}

Equation:

{ \boxed{ \tt{y =  -  \frac{2}{3} x - 5}}}

8 0
2 years ago
True of false: 0.4&lt; 0.400​
LenaWriter [7]

Answer:

false

Step-by-step explanation:

the are the same jus5 one has more zero afterwards

8 0
3 years ago
Read 2 more answers
A manufacturer is designing a flashlight. For the flashlight to emit a focused beam, the bulb needs to be on the central axis of
aalyn [17]
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12

Source:
http://www.1728.org/quadr4.htm




5 0
3 years ago
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